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Dafna11 [192]
3 years ago
11

How many liters of space are in 4.00x10^22 of O2 occupy at STP

Chemistry
1 answer:
irinina [24]3 years ago
5 0

Answer:

V O2 = 1.623 L

Explanation:

  • 1 mol ≡ 6.022 E23 molecules

∴ molecules O2 = 4.00 E22 molecules

⇒ moles O2 = (4.00 E22 molecules O2)×(mol O2/6.022 E23 molecules)

⇒ moles O2 = 0.0664 moles

at STP:

∴ T = 25°C ≅ 298 K

∴ P = 1 atm

assuming ideal gas:

∴ V = RTn/P

⇒ V O2 = ((0.082 atm.L/K.mol)(298 K)(0.0664 mol))/( 1 atm)

⇒ V O2 = 1.623 L

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2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder
damaskus [11]

Answer:

<h2>7.54 atm </h2>

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

P_2 =  \frac{P_1V_1}{V_2}  \\

where

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From the question we have

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We have the final answer as

<h3>7.54 atm </h3>

Hope this helps you

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