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marysya [2.9K]
2 years ago
6

Points and their residual values are shown in the table. a 3-column table with 5 rows. the first column is labeled x with entrie

s 1, 2, 3, 4, 5. the second column is labeled y with entries 2, 3.5, 5, 6.1, 8. the third column is labeled residual value with entries negative 0.4, 0.7, negative 0.2, negative 0.6. which residual value is the farthest from the line of best fit? 0.19 0.7 2 8
Mathematics
1 answer:
maksim [4K]2 years ago
6 0

The residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

<h3>What is residual value?</h3>

The residual value is the estimated value which is calculated for the end of the lease terms for a fixed asset.

Points and their residual values are shown in the table. A 3-column table with 5 rows.

  •  x                               1,     2,     3,     4,     5.
  •  y                               2,   3.5,   5,    6.1,    8.
  • Residual Value       -0.4, 0.7,  -0.2, -0.6   0

The simple regression line can be represented as,

\hat y=\alpha +\beta X+\hat e

Here α is the constant, β is the slope and <em>e </em>is the residue.

The point which is farthest from the best fit of the line is 3.5. At y=3.5, the value of residue is 0.7.

Thus, the residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

Learn more about the residual value here;

brainly.com/question/1168961

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An insurance company issues life insurance policies in three separate categories: standard,preferred,and ultra- preferred. Of th
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Answer:

a) 0.0002

b) 0.0057

c) 0.0364

Step-by-step explanation:

Lets start by stating the probabilities of a person belonging to each policy:

Standard: 0.3

Preferred: 0.5

Ultra- Preferred: 0.2

The probability of person belonging to each policy AND dying in the next year:

Standard: 0.3 x 0.015 = 0.0045

Preferred: 0.5 x 0.002 = 0.001

Ultra- Preferred: 0.2 x 0.001 = 0.0002

a) The probability a ultra - preferred policy holder dies in the next year is 0.001. To find the probability of a person being both a ultra - preferred policy holder AND die in the next year is: 0.001 x 0.2= 0.0002

b)  The probability is given by adding the probabilities calculated before :

0.0045 + 0.001 + 0.0002 = 0.0057

c) We use the results above again. This is 0.0002 / (0.001 + 0.0045). The answer comes out to be 0.0364

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An automobile manufacturer has given its van a 59.5 miles/gallon (MPG) rating. An independent testing firm has been contracted t
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Answer:

The pvalue of the test is 0.0124 < 0.1, which means that there is sufficient evidence at the 0.1 level to support the testing firm's claim.

Step-by-step explanation:

An automobile manufacturer has given its van a 59.5 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the actual MPG for this van since it is believed that the van has an incorrect manufacturer's MPG rating:

At the null hypothesis, we test if the mean is the same, that is:

H_0: \mu = 59.5

At the alternate hypothesis, we test that it is different, that is:

H_a: \mu \neq 59.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

59.5 is tested at the null hypothesis:

This means that \mu = 59.5

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This means that n = 250, X = 59.2, \sigma = 1.9

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

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Pvalue of the test and decision:

The pvalue of the test is the probability of finding a mean that differs from 59.5 by at least 0.3, which is P(|Z|>-2.5), which is 2 multiplied by the pvalue of Z = -2.5.

Looking at the z-table, Z = -2.5 has a pvalue of 0.0062

2*0.0062 = 0.0124

The pvalue of the test is 0.0124 < 0.1, which means that there is sufficient evidence at the 0.1 level to support the testing firm's claim.

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Step-by-step explanation:

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