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marysya [2.9K]
2 years ago
6

Points and their residual values are shown in the table. a 3-column table with 5 rows. the first column is labeled x with entrie

s 1, 2, 3, 4, 5. the second column is labeled y with entries 2, 3.5, 5, 6.1, 8. the third column is labeled residual value with entries negative 0.4, 0.7, negative 0.2, negative 0.6. which residual value is the farthest from the line of best fit? 0.19 0.7 2 8
Mathematics
1 answer:
maksim [4K]2 years ago
6 0

The residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

<h3>What is residual value?</h3>

The residual value is the estimated value which is calculated for the end of the lease terms for a fixed asset.

Points and their residual values are shown in the table. A 3-column table with 5 rows.

  •  x                               1,     2,     3,     4,     5.
  •  y                               2,   3.5,   5,    6.1,    8.
  • Residual Value       -0.4, 0.7,  -0.2, -0.6   0

The simple regression line can be represented as,

\hat y=\alpha +\beta X+\hat e

Here α is the constant, β is the slope and <em>e </em>is the residue.

The point which is farthest from the best fit of the line is 3.5. At y=3.5, the value of residue is 0.7.

Thus, the residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.

Learn more about the residual value here;

brainly.com/question/1168961

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3 years ago
Mr. Thomas drove 75 miles in May. He drove 6 times as many miles in July as he did in May. He
harkovskaia [24]

Answer:

1800 miles

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__________________________________________________

Another condition given   that miles driven in June is 4 times of miles driven by Mr. Thomas in July(450miles as calculated above).

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8 0
3 years ago
|j|=|2j+3| please help me
Softa [21]
Simplifying
j = (2j + 3)

Reorder the terms:
j = (3 + 2j)

Remove parenthesis around (3 + 2j)
j = 3 + 2j

Solving
j = 3 + 2j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-2j' to each side of the equation.
j + -2j = 3 + 2j + -2j

Combine like terms: j + -2j = -1j
-1j = 3 + 2j + -2j

Combine like terms: 2j + -2j = 0
-1j = 3 + 0
-1j = 3

Divide each side by '-1'.
j = -3

Simplifying
j = -3
8 0
3 years ago
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