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sdas [7]
2 years ago
8

A round wastepaper basket with a 0.15-m radius opening is in a uniform electric field of 300n/c, perpendicular to the opening. t

he total flux through the sides and bottom, in n · m^2 c, is
SAT
1 answer:
Andrews [41]2 years ago
4 0

The total flux through the sides and bottom in nm^2 c, is 84.78Nm²/C

<h3>What is Gauss' law?</h3>

Gauss' law states describes what an electric field will look like due to a known distribution of electric charge.

The equation that represents Gauss' law is;

Total flux = Electric charges × Area

Where area of a sphere =4πr²

Total flux = Electric charges × 4πr²

Electric charges = 300n/c

Radius = 0.15-m

Therefore total flux = 300× 4× π× 0.15²

= 300 × 4 × 3.14 × 0.0225

= 84.78Nm²/C

Therefore, the total flux through the sides and bottom in nm^2 c, is 84.78Nm²/C

Learn more about electric charges here:

brainly.com/question/24786034

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