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Allisa [31]
3 years ago
8

How do you add tax to an equation

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0
Where i live it’s 12% so let’s say you bought a item which is $20 you would times 20 by 0.12 and you’d get 2.4 so the. you’d add the two numbers and it would equal $22.4
Serhud [2]3 years ago
5 0
You multiply it by the percent by your state (eg. california is 7.5%, so you multiply x amount by .075)
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Given that MQL =180° and XQR = 180°, which equation could be used to solve problems involving the relationships
Ganezh [65]

Answer:

Option A is the right answer.

146-4b = 122-1b

Reason: vertical angles

8 0
3 years ago
PLEASE I NEED HELP!
NARA [144]
Fourth one i think (the way u typed the q is confusing)
3 0
3 years ago
Read 2 more answers
Expand each expression
matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

3 0
3 years ago
Read 2 more answers
A cell phone provider classifies its customers as Low users (less than 400 minutesper month) or High users (400 or more minutes
Svet_ta [14]

Answer:

a ) See step by step explanation

b) 50%   and  50%

Step-by-step explanation:

The definition of type of user x is:

if x < 400 minutes  per month  low user

if x > 400 minutes per month  high user

The value for these states are of course yes  or no  ( the user is low or high user)

Then:

if the user is low today  xt  (0)    we have the probability of 80% ( 0,8) of have the user in the same condition and 20% (0,2) of having him or her as high user

xt = 1      

If the user is high today xt (1) is high today we have the probability of 70% ( 0,7) of having  the user in the same condition and 30% (0,3) of having him or her as high user

a) Then we construct the stochastic matrix

 Type of user

         (xt)               xt         xt+1  

      Low (0) or L   0,8        0,2

     High(1)  or H   0,3        0,7

The resulting equation system is:

xt  =  0,8* xt  +  0,2* xt+1

xt+1  = 0,3*xt + 0,7* xt+1

1  =  xt + xt+1

Solving for variables         xt+1  =  1  - xt

xt  = 0,8*xt + ( 1 - xt ) * 0,2

xt - 0,8*xt = 0,2 - 0,2xt

xt - 0,6*xt = 0,2

0,4*xt = 0,2

xt = 0,5       and     xt+1  = 0,5

b)  If in January 0,5  ( 50%) of customesr were  low user

In february  teh % of low user customer wll be

xt  =  0,8* xt  +  0,2* xt+1

0,5 = 0,8*0,5 + 0,2*xt+1

0,5 = 0,4 + 0,2 *xt+1

0,1/0,2 = xt+1        xt+1 = 0,5       or   50%

The same answer for March

7 0
3 years ago
The amount of gasoline sold each month to customers at Bob's Exxon station in downtown Navasota is a random variable. This rando
swat32

Answer:

The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month

P(X≥ 2800) = P(Z₁≥1.5) = 0.0768

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Mean of the Population (μ) = 2500 gallons

Standard deviation of the population (σ) =200 gallons

Let 'X' be a random variable in Normal distribution

Given X = 2800

Z = \frac{x-mean}{S.D} = \frac{2800-2500}{200} = 1.5

<u><em>Step(ii):-</em></u>

The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month

P(X≥ 2800) = P(Z₁≥1.5)

                  = 0.5 - A(Z₁)

                 =  0.5 - A(1.5)

                 =   0.5 -0.4232    ( from normal table)

                = 0.0768

<u><em>Conclusion</em></u>:-

The probability that Bob will win that wonderful trip on the basis of his gasoline sales this month

P(X≥ 2800) = P(Z₁≥1.5) = 0.0768

               

3 0
3 years ago
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