Answer:
Step-by-step explanation:
<u><em>Note:</em></u><em> It seems typo in the question. 5% should read 59.</em>
Let 3 credit courses = x, 4 credit courses = y
<u>As per given we have following equations:</u>
<u>Solve the system by elimination. Multiply the first equation by 4 and subtract the second one:</u>
- 4(x + y) - (3x + 4y) = 4(18) - 59
- 4x + 4y - 3x - 4y = 72 - 59
- x = 13
The answer is 13
Correct choice is A
9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
C - (0.40c - 0.15) - (0.60c - 0.20)
I hope this helps :)
The answer to this question is : <span>Megohm meter</span>