For the left graph (y=2x^2), B) the graph will become narrower.
For the 2nd one (inequality):
Therefore it is D)
I think the last one is C) 3 real and 2 imaginary zeros. Because the three real ones are where it crosses the x-axis.
Answer:
h= 14
Step-by-step explanation:
7h-5(3h-8)= -72 PEDMAS Parenthesis first
7h-15h+40= -72 combine like terms
-8h+40= -72 subtract 40 from both sides
-8h=-112 divide by -8
h=14
2:6 so simplify it 1:3. This means the scale ratio is 1:3 for the figures. To find w, sub in the 3 from the smaller figure to the ratio so 3×3=9, 3:9 w=9
The sum of x^2−3xy−y^2 and 2x^2+5xy−4y^2:
x^2−3xy−y^2 + 2x^2+5xy−4y^2
= 3x^2 + 2xy - 5y^2
From 6x^2−7xy+8y^2 subtract the sum of x^2−3xy−y^2 and 2x^2+5xy−4y^2:
6x^2−7xy+8y^2 - (3x^2 + 2xy - 5y^2)
= 6x^2−7xy+8y^2 - 3x^2 - 2xy + 5y^2
= 3x^2−9xy + 13y^2
Answer
3x^2−9xy + 13y^2
<span> 2(11 + y) = 22 + 2y ...expand by using distributive property
hope it helps</span>