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allsm [11]
3 years ago
6

each time kim pour water from a jug into a glass, exactly 10% of the water remaining in the jug is used. What is the minimum num

ber of times that she must pour water into a glass so that less than half the water remains in thd jug?
Mathematics
1 answer:
Gnoma [55]3 years ago
4 0

The <em><u>correct answer</u></em> is:

At least 7 times.

Explanation:

Since 10% of the water in the jug is removed each time, this means that 100-10=90% of the water remains.

After two times, we would have 0.9(0.9) = 0.81 = 81% of the water; each time she pours, the number of times 0.9 is multiplied by itself changes.  This makes this an exponential inequality (it is not an equation, as we want "less than half of the water"):

0.5 < 0.9^x

To solve this, we will use logarithms:

\log_{0.9}(0.5)

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Answer:

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Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 400 and a standard deviation of 60.

This means that \mu = 400, \sigma = 60

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We have to find X when Z = 3. So

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3 = \frac{X - 400}{60}

X - 400 = 3*60

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