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2 years ago

Please help me!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

MAXImum [283]2 years ago

8 0

Answer:

120(I'm not definitely sure)

Step-by-step explanation:

IQR= Q3- Q1= 170 - 50 = 120

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Megan has a large packing box shaped as a cube with a volume of 216 cubic feet.

Flura [38]

Answer:

s = 6 feet

Step-by-step explanation:

Given that,

The volume of the cube, V = 216 feet³

We need to find the side length for the cubical box. We know that the volume of the cube is given by :

$V=s^3$ , s is the side length of the box.

So,

$s={V}^{1/3}\\\\s={216}^{1/3}\\\\s=6\ feet$

So, the side length for the cubical box is equal to 6 feet.

6 0

3 years ago

1.4t-0.4(t-3.1)=5.8 please help !!

Svetllana [295]

Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56

4 0

3 years ago

Select the equivalent expression.<br> (24 • y4): =?<br> Choose 1 answer:<br> What’s the answer?

melomori [17]

Answer:

look at the image ......

5 0

3 years ago

If sec(theta) =25/24, find cot(theta) (Picture provided)

larisa [96]

Answer:

Step-by-step explanation:

By the definition,

$\sec \theta=\dfrac{\text{hypotenuse}}{\text{adjacent leg}}.$

If $\sec \theta=\dfrac{25}{24},$ we can consider right triangle with hypotenuse 25 un. and adjacent leg 24 un. By the Pythagorean theorem,

$\text{hypotenuse}^2=\text{adjacent leg}^2+\text{opposite leg}^2,\\ \\\text{opposite leg}^2=25^2-24^2,\\ \\\text{opposite leg}^2=625-576,\\ \\\text{opposite leg}^2=49,\\ \\\text{opposite leg}=7\ un.$

So,

$\cot \theta=\dfrac{\text{adjacent leg}}{\text{opposite leg}}=\dfrac{24}{7}.$

8 0

3 years ago

Read 2 more answers

Pls help I’ll make brainlest and give extra points

allochka39001 [22]

Answer:

p>-3 open circle going to the right

$m\leq -4$ closed circle going to the left

n<5 open circle going to the left

$h\geq 2$ closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

Step-by-step explanation:

Before I answer these here are some good notes

If the inequality sign is < or > then the circle is going to be open

If the inequality sign is $\leq or\geq$ then the circle is going to be closed

If the inequality sign is facing the variable (ex: x>3) then the line is going to be going to the right

If the inequality sign is facing the constant (ex: x<3) then the line is going to be going to the left

p>-3 open circle going to the right

$m\leq -4$ closed circle going to the left

n<5 open circle going to the left

$h\geq 2$ closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

6 0

2 years ago