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Nadusha1986 [10]
2 years ago
6

Please help me!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
MAXImum [283]2 years ago
8 0

Answer:

120(I'm not definitely sure)

Step-by-step explanation:

IQR= Q3- Q1= 170 - 50 = 120

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Megan has a large packing box shaped as a cube with a volume of 216 cubic feet.
Flura [38]

Answer:

s = 6 feet

Step-by-step explanation:

Given that,

The volume of the cube, V = 216 feet³

We need to find the side length for the cubical box. We know that the volume of the cube is given by :

V=s^3, s is the side length of the box.

So,

s={V}^{1/3}\\\\s={216}^{1/3}\\\\s=6\ feet

So, the side length for the cubical box is equal to 6 feet.

6 0
3 years ago
1.4t-0.4(t-3.1)=5.8 please help !!
Svetllana [295]
Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56
4 0
3 years ago
Select the equivalent expression.<br> (24 • y4): =?<br> Choose 1 answer:<br> What’s the answer?
melomori [17]

Answer:

look at the image ......

5 0
3 years ago
If sec(theta) =25/24, find cot(theta) (Picture provided)
larisa [96]

Answer:

B

Step-by-step explanation:

By the definition,

\sec \theta=\dfrac{\text{hypotenuse}}{\text{adjacent leg}}.

If \sec \theta=\dfrac{25}{24}, we can consider right triangle with hypotenuse 25 un. and adjacent leg 24 un. By the Pythagorean theorem,

\text{hypotenuse}^2=\text{adjacent leg}^2+\text{opposite leg}^2,\\ \\\text{opposite leg}^2=25^2-24^2,\\ \\\text{opposite leg}^2=625-576,\\ \\\text{opposite leg}^2=49,\\ \\\text{opposite leg}=7\ un.

So,

\cot \theta=\dfrac{\text{adjacent leg}}{\text{opposite leg}}=\dfrac{24}{7}.

8 0
3 years ago
Read 2 more answers
Pls help I’ll make brainlest and give extra points
allochka39001 [22]

Answer:

p>-3 open circle going to the right

m\leq -4 closed circle going to the left

n<5 open circle going to the left

h\geq 2 closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

Step-by-step explanation:

Before I answer these here are some good notes

If the inequality sign is < or > then the circle is going to be open

If the inequality sign is \leq  or\geq then the circle is going to be closed

If the inequality sign is facing the variable (ex: x>3) then the line is going to be going to the right

If the inequality sign is facing the constant (ex: x<3) then the line is going to be going to the left

p>-3 open circle going to the right

m\leq -4 closed circle going to the left

n<5 open circle going to the left

h\geq 2 closed circle going to the right

1>x open circle going to the left

-1=d just a closed circle

6 0
2 years ago
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