Answer:
<em>Choice: B.</em>
Step-by-step explanation:
<u>Operations With Functions</u>
Given the functions:
![f(x)=\sqrt[3]{12x+1}+4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4)

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

![(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%28%5Csqrt%5B3%5D%7B12x%2B1%7D%2B4%29)
Operating:
![(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4](https://tex.z-dn.net/?f=%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%2B6%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D-4)
Joining like terms:
![\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}](https://tex.z-dn.net/?f=%5Cboxed%7B%28g-f%29%28x%29%3D%20%5Clog%28x-3%29%20-%20%5Csqrt%5B3%5D%7B12x%2B1%7D%2B2%7D)
Choice: B.
One of the fractions that’s equal to
is 
<u>Solution:</u>
Given that , we have to find fractions which has the same value as that of the fraction
Now, we know that, there are several fractions with values equal to
To find them, just multiply the numerator and denominator by the same number.

Therefore,
is equal to 
We can do the same with 4, to get
, or any other number beyond that.
Hence, one of the fractions that’s equal to
is 
Answer:
x=-10
Step-by-step explanation:
the picture is showing
1+1= -1 + -1 + -1 + -1 + -1 + -1 + -1 + -1 + -x
simplified its:
2= -8 + -x
I think that the answer is x=-10 cuz if u did -8 - -10 then the two negatives make a positive and it makes 2 but idk if the minus sign before the x means minus or negative so this might be the answer but dont blame me if im wrong. I warned you. If its right plz write that.
1/6³ is simply multiplying the fraction 3 times.
or the numerator 3 times and the denominator 3 times.
It can be: 1/6 * 1/6 * 1/6 = <u>1 * 1 * 1 </u> = <u> 1 </u>
6 * 6 * 6 216<u />
or <u> 1³ </u> = <u> 1 </u>
6³ 216