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Valentin [98]
2 years ago
7

Jenni plots her house and yard on a computer. she determines that the circle that defines the part of the front yard that gets w

atered by the sprinkler is (x−9)2 (y 11)2=16. what is the diameter, in meters, of the circular area that gets watered by the sprinkler? 4 m 8 m 16 m 32 m
Mathematics
1 answer:
butalik [34]2 years ago
3 0

The length of the diameter, in meters, of the circular area that gets watered by the sprinkler for this condition is given by: Option B: 8 m

<h3>What is the equation of the circle of radius r units, centered at (x,y) ?</h3>

If a circle O has radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane, then, its equation is given as:

(x-h)^2 + (y-k)^2 = r^2

For this case, the equation of the circle that models tha circular area considered is:

(x-9)^2 + (y+11)^2=16

Writing this in standard form and comparing it with the standard equation, we get:

(x-9)^2 + (y+11)^2=16\\(x-9)^2 + (y - (-11) )^2  = 4^2 (didn't took (-4)² = 16 since radius cannot be negative).

Thus, we get center's coordinate as (9,-11) and radius of 4

The diameter of that circular area = twice of radius of the circle which models it = 2 × 4 = 8 meters.

Thus, the length of the diameter, in meters, of the circular area that gets watered by the sprinkler for this condition is given by: Option B: 8 m

Learn more about equation of a circle here:

brainly.com/question/10165274

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PLEASE ANSWER ASAP TODAY WILL GIVE BRAINLIEST TO FIRST RIGHT ANSWER.
Lisa [10]

Answer:

y-7=3(x-9)

Step-by-step explanation:

It appears they want your answer in point-slope form, which is identified by the equation y-y1=m(x-x1)

Step 1: Find the slope (m)

m=(y2-y1)/(x2-x1)

m=(-8-7)/(4-9)

m=(-15)/(-5)

m=3

The slope is m=3

Step 2: Plug in m, y1, and x1

y-y1=m(x-x1)

y-7=3(x-9)

Therefore our final equation is y-7=3(x-9)

7 0
3 years ago
I need help with #39-42, please explain.
shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

l=m\sqrt{n}

Question 39:

When ' n ' increase, the \sqrt{n} will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As n increases and m stays constant , l <u>increases</u>

-------

Question 40:

Solving the equation for m, we get

l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As l increase and n stays constant, m <em><u>increases</u></em>

------

For question 41 & 42, we need to use the below equation to complete the sentence

r=s^2/t^2

Question 41:

When s is triped, the equation will be...

r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2}   =9s^2/t^2

Solution for question 41:

If s is tripled and t stays constant, r is multiplied by <em><u>9</u></em>

--------

Question 42:

When t is doubled, the equation will be...

r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\   \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}

Solution for 42:

If t doubled and s stays constant, r is multiplied by <em><u>1/4 or 0.25</u></em>


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