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djverab [1.8K]
3 years ago
15

What is 55/99 Rounded to the nearest half

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer:  1/2

Step-by-step explanation:

Xelga [282]3 years ago
4 0

This human above is correct

Yea

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Pick the correct answer<br> Help me please thank you :)
Andrej [43]
Answer: D
Steps: In partially legible pic below. Sorry not the best explanation

4 0
2 years ago
Volume in barrels of a tank 38.622 feet in diameter by 16 feet in height
Gnoma [55]
 3.14 * 19.311^2 = 60.63654
 60.63654 * 19.311 = 1170.95222394
1170.95222394 * 16 = 18744.738366545
<span>18744.738366545 foot^<span>3
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7 0
3 years ago
Which graph represents the function f(x)=−3x−2?
LenaWriter [7]

Answer:

Top left

Step-by-step explanation:

We can plug in the y intercept to find which graph has the correct one.

x = 0 is y intercept

Thus

f(0) = -3^0-2 \\f(0) = -1-2\\f(0)=-3

At this point we known the y intercept is -3 so both graph in the left is considerable.

Notice that the base is the negative, thus the graph would goes down. Therefore the top left would be correct.

4 0
4 years ago
The equation of a function is
VikaD [51]
The answer is B. 53
12 times 5 then sub 7
hope it helps
3 0
3 years ago
Read 2 more answers
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
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