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djverab [1.8K]
3 years ago
15

What is 55/99 Rounded to the nearest half

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer:  1/2

Step-by-step explanation:

Xelga [282]3 years ago
4 0

This human above is correct

Yea

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The charity gala costs $5.17 for every attendee. How many attendees can there be, at most, if the budget for the charity gala is
Elodia [21]

Answer:

15 people are able to be at the charity gala because 77:55 divided by 5:17.

3 0
3 years ago
Simplify the expression 3^-8× 34.
Alborosie

Answer:

= \frac{34}{6561}

Step-by-step explanation:

= 3^{-8}\times \:34\\= 34\times \frac{1}{3^{8} } \\= \frac{1\times \:34}{3^{8} } \\= \frac{34}{3^{8} } \\= \frac{34}{6561}

5 0
3 years ago
Mary said that the temperature outside on two differnt days had an absolute value 20. Kate said she was wrong because the temper
TiliK225 [7]

Answer:

Mary is correct we don’t know the temperature but it can be implied that one is 20 and the other is -20 because of absolute value which is the distance a number away from zero that means that you have two answers or two days in this case that both have an absolute value of 20

Step-by-step explanation:

5 0
2 years ago
Iron has a density of 7.9 g/cm³. Gold has a density of 19.3 g/cm³.
alexandr402 [8]
Density = m/v
3.86kg=3860g
d= 3860/200
= 19.3g/cm^3
therefore it is gold.
7 0
2 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
3 years ago
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