Answer:
the answer to your question is obviously "rational"
Answer:
Here is the Python program:
COOKIES_PER_BAG = 40 #sets constant value for bag of cookies
SERVINGS_PER_BAG = 10 #sets constant value for serving in bag
CALORIES_PER_SERVING = 300 #sets constant value servings per bag
cookies = int(input("How many cookies did you eat? ")) #prompts user to input how many cookies he or she ate
totalCalories = cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG)); #computes total calories consumed by user
print("Total calories consumed:",totalCalories) #displays the computed value of totalCalories consumed
Explanation:
The algorithm is:
- Start
- Declare constants COOKIES_PER_BAG, SERVINGS_PER_BAG and CALORIES_PER_SERVING
- Set COOKIES_PER_BAG to 40
- Set SERVINGS_PER_BAG to 10
- Set CALORIES_PER_SERVING to 300
- Input cookies
- Calculate totalCalories: totalCalories ← cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG))
- Display totalCalories
I will explain the program with an example:
Lets say user enters 5 as cookies he or she ate so
cookies = 5
Now total calories are computed as:
totalCalories = cookies * (CALORIES_PER_SERVING / (COOKIES_PER_BAG / SERVINGS_PER_BAG));
This becomes:
totalCalories = 5 * (300/40/10)
totalCalories = 5 * (300/4)
totalCalories = 5 * 75
totalCalories = 375
The screenshot of program along with its output is attached.
Answer:
#include <iostream>
using namespace std;
int main()
{
string str;
cout<<"Enter the string: ";
cin>>str;
for(int i=0;str[i]!='\0';i++){
if(str[i]=='e'){
str[i]='x';
}
}
cout<<"the string is: "<<str<<endl;
return 0;
}
Explanation:
First, include the library iostream for using the input/output instructions.
Create the main function and declare the variables.
Then, use the cout instruction and print the message on the screen.
cin store the string enter by the user into a variable.
After that, take a for loop and if-else statement for checking the condition if the string contains the 'e', then change that alphabet to 'x'.
This process continues until the string not empty.
Finally, print the updated string.