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Murrr4er [49]
3 years ago
7

Assume we are using the simple model for floating-point representation as given in this book (the representation uses a 14-bit f

ormat, 5 bits for the exponent with a bias of 15, a normalized mantissa of 8 bits, and a single sign bit for the number). What decimal value (no leading/trailing zeros) for the sum of 01011011001000 and 00111010000000 is the computer actually storing?
Computers and Technology
1 answer:
Artemon [7]3 years ago
3 0

Answer:

The representation of 100.0 in the floating-point representation is computed as follows: First convert the given number 100.0 in the binary form. 10010 = 11001002 the binary representation.

Explanation:

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16. Budget Analysis Write a program that asks the user to enter the amount that he or she has budgeted for a month. A loop shoul
strojnjashka [21]

Answer:

import java.util.Scanner;

public class num8 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter month's budget");

       double monthBudget = in.nextDouble();

       double totalExpenses = 0.0;

       double n;

       do{

           System.out.println("Enter expenses Enter zero to stop");

           n = in.nextDouble();

           totalExpenses += n;

       }while(n>0);

       System.out.println("Total expenses is "+totalExpenses);

System.out.println("The amount over your budget is "+ Math.abs(monthBudget-totalExpenses));

   }

}

Explanation:

  • Using Java programming language
  • Prompt user for month's budget
  • Use Scanner class to receive and store the amount entered in a variable
  • Use a do while loop to continuously request user to enter amount of expenses
  • Use a variable totalExpenses to add up all the expenses inside the do while loop
  • Terminate the loop when user enters 0 as amount.
  • Subtract totalExpenses from monthBudget and display the difference as the amount over the budget

6 0
3 years ago
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

8 0
4 years ago
7.12 LAB: Even/odd values in a list
Korvikt [17]

The odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is zero (0).

<h3>What are even numbers and odd numbers?</h3>

The even numbers can be found in a list because they are divisible by two and the remainder of this equation is always zero (0).

Conversely, odd numbers are those that cannot be divided exactly into exact entire numbers (e.g., 3, 5, etc).

The odd numbers in a list can be calculated by the equation ON (odd numbers): n/2 × [f + g], where 'f' is the first number and 'g' is the last number.

In conclusion, the odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is 0.

Learn more about odd numbers here:

brainly.com/question/2263958

#SPJ1

4 0
2 years ago
. Java is a high-level language.. true or false?
frutty [35]

Answer:

the answer is true. it is a high level language

4 0
3 years ago
It is 10PM and you are inside in the middle of a large building. Your cell phone is dead so you cannot use wifi or cell signals
kupik [55]

<em>The answer is: your GPS unit cannot send signals to the satellite when it cannot reach it by line of sight. </em>

<em> </em>

<em>GPS signals are based on frequencies that can be blocked by solid objects (like walls and roofs). A GPS device is using a series of satellites to detect and see where it is physically located. These frequencies are sent from these plates (satellites) and we cannot expect it to go through all kinds of barriers. When you use a GPS inside a building, a wide variety of physical barriers and potential interference sources make it difficult for the device to detect your location accurately. </em>

<em> </em>

<em />

4 0
3 years ago
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