Question

Part 1: How's the weather? A. Investigate the weather forecast in your city. Record the high and low temperatures that are forecast for the next 7 days in the table below. In the columns titled, Difference," record the change in temperature from the day before. To do this, subtract the previous temperature from the current temperature Be sure to use positive and negative numbers as needed! For example, if yesterday’s temperature was 70 and today’s temperature was 65, the difference is 65 – 70 = -5. Date High Temperature Subtract previous temperature from current temperature Difference Low Temperature Subtract previous temperature from current temperature Difference 1 09/15/2021 89 -N/A- -N/A- 75 -N/A- -N/A- 2 09/16/2021 91 91-89 2 77 77-75 2 3 09/17/2021 92 92-91 1 75 75-77 -2 4 09/18/2021 91 91-92 -1 77 77-75 2 5 09/19/2021 90 90-91 -1 78 78-77 1 6 09/20/2021 89 89-90 -1 78 78-78 0 7 09/21/2021 87 87-89 -2 78 78-78 0 B. Note: The columns for Day One's subtraction and difference cannot be filled in. As this is the first data point, there is no previous temperature to subtract. C. Write a mathematical expression using the information from your table to answer the following questions: 1. What is the mean change in the forecasted high temperatures? Remember, this can be found by averaging the values in the Difference column for the high temperatures. Show your work and steps. If your answer is not an integer, explain what two integers your answer is between.
2. What is the mean change in the forecasted low temperatures? Remember, this can be found by averaging the values in the Difference column for the low temperatures. If your answer is not an integer, explain what two integers your answer is between. ____________________
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Answer 1

Using the mean concept, it is found that:

1. The mean change in the forecasted high temperatures is of -0.33ºC.

2. The mean change in the forecasted low temperatures is of 0.5ºC.

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The mean of data-set is given by the sum of all observations divided by the number of observations.

Item 1:

The changes in the high temperature are: 2, 1, -1, -1, -1, -2

Thus:

$M = \frac{2 + 1 - 1 - 1 - 1 - 2}{6} = -0.33$

The mean change in the forecasted high temperatures is of -0.33ºC.

Item 2:

The changes in the low temperature are: 2, -2, 2, 1, 0, 0.

$M = \frac{2 - 2 + 2 + 1 + 0 + 0}{6} = 0.5$

The mean change in the forecasted low temperatures is of 0.5ºC.

A similar problem is given at brainly.com/question/24754716