Which of the following could be the equation of the function below?

A recipe for fluffy slime calls for 3 3/4 cups of shaving cream, 1/2 cup of glue, 1/2 teaspoon of baking soda and 1 1/2 tablespo

DIA [1.3K]

Answer:

75/4 cups (or 18-3/4 cups)

Step-by-step explanation:

Ignore all the wording about glue, baking soda and saline.

What this question reduces to is that the recipe for :

2 people ---> requires 3 3/4 cups (or 15/4 cups) of shaving cream

10 people ----> requires 5 times the amount of shaving cream needed for 2 people

Hence shaving cream needed for 10 people

= 5 x 3 3/4 cups

= 5 x 15/4 cups

= 75/4 cups (or 18-3/4 cups)

3 0

2 years ago

Help pls i need this luv u guys <33

coldgirl [10]

So this is so easy
the answer is33
pay attention what i’m saying:
if you have a circle like this and you have arc if the arc doesnt pass the center of the circle and fit to the environment of circle the measure of angle is half of the measure of arc

3 0

2 years ago

$250 at 4% for 1 year<br> What is the balance of the account?

Ksju [112]

Answer:

Balance is $260.

Step-by-step explanation:

4% of $250

= 0.04 * 250

= $10.

250 + 10 = $260.

3 0

2 years ago

Read 2 more answers

Can someone help me with all this? Lol idk any of this and E-learning sucks I need to show my work as well

Margarita [4]

Answer:

1a) 230 feet

1b) 3.75s

1c) t=7.54s

2) t=2s

3) t=2.32s

Step-by-step explanation:

The equation that models Brett's last home run is $h(t)=-16t^2+120t+5$

We need to complete the square to obtain the function in the vertex form:

$h(t)=-16(t^2-7.5t)+5$

$h(t)=-16(t^2-7.5t+3.75^2)+5+-16(-3.75)^2$

$h(t)=-16(t-3.75)^2+230$

1a) The vertex is (3.75,230).The maximum value is the y-coordinate of the vertex, which is 230 feet.

1b) The time it takes to reach the maximum value is the x-coordinate of the vertex. It reach the maximum heigth after t=3.75 seconds

1c) To find the time the ball hit the ground, we equate the h(t)=0 and solve for t.

$-16(t-3.75)^2+230=0$

$-16(t-3.75)^2=-230$

$(t-3.75)^2=14.375$

$t-3.75=\pm \sqrt{14.375}$

$t=3.75\pm \sqrt{14.375}$

$t=3.75\pm 3.79$

$t=3.75-3.79\:\:or\:t=3.75+3.79$

$t=3.75-3.79\:\:or\:t=3.75+3.79\\t=-0.04\:\:or\:t=7.54$

The time is positive, so the ball hit the ground after 7.54 seconds.

Question 2)

The function that models the amusement ride is $h(t)=-16t^2+64t+60$

We want to find the time it takes for the riders to reach the maximum height.

This time is given by: $t=-\frac{b}{2a}$

Comparing $h(t)=-16t^2+64t+60$ to $h(t)=at^2+bt+c$ we have a=-16, b=64, c=60.

We substitute to obtain:

$t=-\frac{64}{2*-16} \\t=-\frac{64}{-32} \\t=2$

Hence it took 2 seconds to rech the maximum height.

Question 3)

The equation that models the height f the catridge is $h(t)=-16t^2+35t+5$

To find the time that the catridge will land, we equate the function to zero and solve for t.

$-16t^2+35t+5=0$

This is a quadratic equation with =-16, b=35, an c=5

The solution is given by:

$t=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute the values to get:

$t=\frac{-35\pm \sqrt{35^2-4*-16*5} }{2*-16}$

This gives:

$t=\frac{35-\sqrt{1545} }{32} \:or\: t=\frac{35+\sqrt{1545} }{32}$

This simplifies to:

$t=-0.13\:or\: t=2.32$

The time it takes to land must be positive thefore t=2.32 seconds

7 0

2 years ago

Circle F is congruent to circle j, and < EFD ≈

IrinaVladis [17]

Hey there, please provide a picture of the diagram so we can better assist you

3 0

2 years ago