The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Y = cos(x)
sqrt(3)/2 = cos(30º)
dy = -sin(x)*dx
dy = -sin(30º)*(pi/180) = (1/2)*(pi/180)
y + dy = cos(x) - sin(x)dx
y + dy = sqrt(3)/2 - (1/2)*(pi/180) = 0.8573 <span />
250/974 = x/40,000...250 opposed to 974 total = x opposed to 40,000 total cross multiply because this is a proportion 974x = 10,000,000 x = 10,000,000/974 x = 10266.94 rounds to 10,267 <==
