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gulaghasi [49]
3 years ago
9

Which of the following expressions are equivalent to 6 + (-4) - 5 ?

Mathematics
2 answers:
alex41 [277]3 years ago
8 0

Answer:

Step-by-step explanation:

6 + (-4) - 5 = 6 - 4 - 5 = 6 - 9 = -3

A. - (-6 + 4) - 5 = -(-2) - 5 = 2 - 5 = -3

C. 6 - (4 + 5) = 6 - 9 = -3

Gekata [30.6K]3 years ago
6 0

Answer:

A

C

Step-by-step explanation:

A and C gives same result....

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Will mark correct answer brainly.
Furkat [3]

Answer:

Step-by-step explanation:

Volume of Cone =1 \div 3 \times \pi \times r { \times h}^{2}1÷3×π×r×h

2

4 0
2 years ago
Mark wants to maintain an average of 70 on his math tests to remain eligible for sports. So far, he earned scores of 68, 75, 74,
Alex17521 [72]

Answer:

Step-by-step explanation:

(68+75+74+82+88+x)/6=70

(387+x)/6=70

x= 33

6 0
3 years ago
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74
lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

4 0
3 years ago
Please help<br><br>solve this but don't spam<br>​
vfiekz [6]
9x-8=9x-3/2 X3
9x-8=27x-9/2
2(9x-2)=27x-9
18x-4 =27x-9
18x-27x=-9+4
-9x =-5
9x=5
X=5/9 answer
4 0
3 years ago
Convert 8.132132132 ... to a rational expression in the form of a over b , where b ≠ 0.
bezimeni [28]

Let <em>x</em> = 8.132132132...

Then 1000<em>x</em> = 8132.132132132...

Subtract <em>x</em> from 1000<em>x</em> to eliminate the fractional part:

1000<em>x</em> - <em>x</em> = 8132.132132132... - 8.132132132...

999<em>x</em> = 8132 - 8 = 8124

<em>x</em> = 8124/999 = 2708/333

5 0
3 years ago
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