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yanalaym [24]
2 years ago
14

Charlie guesses that his dog weighs 34. 5 pounds. The dog actually weighs 32. 7 pounds. What is the percent error in Charlie’s g

uess, to the nearest tenth of a percent? 0. 05% 0. 5% 5. 2% 5. 5%.
Mathematics
1 answer:
expeople1 [14]2 years ago
3 0

Percent error is the amount of error to actual value, in percent. The percent error in Charlie’s guess is approximately: Option D: 5.5%

<h3>How to calculate the percent error?</h3>

Suppose the actual value and the estimated values after the measurement are obtained. Then we have:

Error = Actual value - Estimated value

To calculate percent error, we will measure how much percent of actual value, the error is, in the estimated value.

\rm Percent \: Error = |\dfrac{Error}{Actual value}|\times 100 \\\\Percent \: Error = | \dfrac{\text{(Actual Value - Estimated Value)}}{Actual value}|\times 100 \\

(here |x| is such that it makes x non negative, thus, |-5| = 5, and |5| = 5)

For the given case, it is specified that:

Actual weight of dog = 32.7 pounds

Guessed weight of dog, by Charlie : 34.5 pounds.

Error = 32.7 - 34.5 = -1.8 pounds

Thus, percent error in Charlie's guess is calculated as:

\text{Percent Error} = |\dfrac{-1.8}{32.7}| \times 100 \approx 5.5\%

Hence, the percent error in Charlie’s guess is obtained approximately is given by: Option D: 5.5%

Learn more about percent error here:

brainly.com/question/25749180

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The Consumer Price Index​ (CPI) is a measure of the change in the cost of goods over time. If 1982 is used as the base year of c
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Answer:

a) y = 3.8 x +100

b) Abs. change= |168.4-167.5|=0.9

So the calculated value is 0.9 points above the actual value.

Relative. Change =\frac{|168.4 -167.5|}{167.5}x100 =0.537%

And the calculated value it's 0.537% higher than the actual value.

c) For this case we can use the slope obtained from the linear model to answer this question, and we can conclude that the CPI is increasing at approximate 3.8 units per year.

Step-by-step explanation:

Data given

1982 , CPI=100

1986, CPI = 191.2

Notation

Let CPI the dependent variable y. And the time th independent variable x.

For this case we want to adjust a linear model givn by the following expression:

y=mx+b

Solution to the problem

Part a

For this case we can find the slope with the following formula:

m =\frac{CPI_{2006}-CPI_{1982}}{2006-1982}

And if we replace we got:

m =\frac{191.2-100}{2006-1982}=3.8

Let X represent the number of years after. Then for 1982 t = 0, and if we replace we can find b:

100 = 3.8(0)+b

And then b=100

So then our linear model is given by:

y = 3.8 x +100

Part b

For this case we need to find the years since 1982 and we got x = 2000-1982=18, and if we rpelace this into our linear model we got:

y = 3.8(18) +100=168.4

And the actual value is 167.5 we can compare the result using absolute change or relative change like this:

Abs. change= |168.4-167.5|=0.9

So the calculated value is 0.9 points above the actual value.

And we can find also the relative change like this:

Relative. Change =\frac{|Calculated -Real|}{Real}x100

And if we replace we got:

Relative. Change =\frac{|168.4 -167.5|}{167.5}x100 =0.537%

And the calculated value it's 0.537% higher than the actual value.

Part c

For this case we can use the slope obtained from the linear model to answer this question, and we can conclude that the CPI is increasing at approximate 3.8 units per year.

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