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lions [1.4K]
3 years ago
12

What’s the lowest common multiple of 120 and 75

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0
<h2>Answer:  600</h2>

Step-by-step explanation:

prime factorization of 75:

75 = 3 × 5 × 5

prime factorization of 120:

120 = 2 × 2 × 2 × 3 × 5

LCM = 2 × 2 × 2 × 3 × 5 × 5

There for the LCM = 600

* HOPEFULLY THIS HELPS:) Mark me the brainliest:)!!

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Simplify sine squared theta divided by the quantity 1 minus sine squared theta..
timama [110]
Answer: tan^2ø
(i’m gonna use ø as theta because i can’t find it)

explanation:
sin^2ø-1=cos^2ø because of one of the pythagorean identities

sin^2ø/cos^2ø is tan^2ø because sin/cos is tan- opposite/hypotenuse divided by adjacent/hypotenuse is opposite/adjacent

hope that helps- you can comment if you need any more explanation :)
3 0
3 years ago
Solve 5.3×0.5 and show work
Inga [223]
5.3 * 0.5 = 2.65
5.3/2=2.65
8 0
3 years ago
I don’t know where to start, I need help.
NeX [460]

Answer:

72 cm^3

Step-by-step explanation:

find the volume of the big block and the volumem of the smaller block and subtract it

(8 x 2 x 5) - (2 x 2 x2)

= 80 cm^3 - 8 cm^3

= 72cm^3

5 0
3 years ago
-7d=56<br><img src="https://tex.z-dn.net/?f=%20-%207%20%3D%2056" id="TexFormula1" title=" - 7 = 56" alt=" - 7 = 56" align="absmi
PtichkaEL [24]
The only thing you need to do is divide 56 by -7. You know the d must be a negative number because negative x negative= positive. So 56 / -7 is -8.
7 0
2 years ago
The binomial x-2 is a factor of the polynomial below. f(x)=x3+x2+nx+10 What is the value of n?
Nutka1998 [239]
<h3>Answer: n = -11</h3>

=========================================================

Explanation:

Since x-2 is a factor of f(x), this means f(2) = 0.

More generally, if x-k is a factor of p(x), then p(k) = 0. This is a special case of the remainder theorem.

So if we plugged x = 2 into f(x), we'd get

f(x) = x^3+x^2+nx+10

f(2) = 2^3+2^2+n(2)+10

f(2) = 8+4+2n+10

f(2) = 2n+22

Set this equal to 0 and solve for n

2n+22 = 0

2n = -22

n = -22/2

n = -11 is the answer

Therefore, x-2 is a factor of f(x) = x^3+x^2-11x+10

Plug x = 2 into that updated f(x) function to find....

f(x) = x^3+x^2-11x+10

f(2) = 2^3+2^2-11(2)+10

f(2) = 8+4-22+10

f(2) = 0

Which confirms our answer.

3 0
3 years ago
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