The one way in which the spread of buddhism in the period before 1450;
- Religion is part of culture and spread as people interact. So therefore, Buddhism spread as the people who believed in it traveled around the world. Leaders who held Buddhist ideas and their territory became Buddhist. It spread along trade routes
For better understanding let's explain how Buddhism spread
- The continuity of Buddhism in the patterns of cultural diffusion between the time period before 1450 was mostly due to the movement along trade routes. An example is movement of Buddhism along the Silk Road and Indian Ocean trade route.
- One of the reasons as to why Buddhism continuously moved along trade routes was because the religion was wild spread and was appealing to merchants who were travelling along these routes.
From the above we can therefore say that the answer The one way in which the spread of buddhism in the period before 1450;
- Religion is part of culture and spread as people interact. So therefore, Buddhism spread as the people who believed in it traveled around the world. Leaders who held Buddhist ideas and their territory became Buddhist. It spread along trade routes, is correct.
Learn more about cultural diffusion from:
brainly.com/question/2035730
Hello oddworld7836!
Factor the expression into an equivalent form 12y² - 75.
By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.
Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,
- a² = 4, a = 2 (√a² = ✓4 = 2)
- b² = 25, b = 5 (√b² = ✓25 = 5)
So, the (4y² + 25) becomes...
Now, bring the 3 (common factor) & rewrite the complete expression.
We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.
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The only reaction that will most likely take place based on the activity series is; C: Ba + Na₂CO₃
<h3>Activity Series</h3>
From the activity series given, we can say that during a displacement reaction, the more reactive metal will always displace the lesser reactive metal from a compound.
Let us look at each of the given options;
A) Ag + FeCl₃
From the activity series, Silver(Ag) is less reactive than Iron(Fe) and as such Silver cannot displace iron from its' compound.
B) Zn + CaO
Zinc (Zn) is a less reactive metal than Calcium (Ca), so it cannot cannot displace Calcium from its' compound.
C) Ba + Na₂CO₃
Barium (Ba) is a more reactive metal than Sodium (Na), and therefore Barium will displace sodium from its compound in a displacement reaction.
D) Cr + KNO₃
Chromium (Cr) is a lesser reactive metal than Potassium (K), and it therefore cannot displace Potassium from its compound.
Complete question is;
Which reaction will most likely take place based on the activity series? Li > K Ba > CaNa > Mn > Zn > Cr> Fe> Cd Ni > H > Sb > Cu > Ag > Pd > Hg > Pt
A. Ag + FeCl₃
B. Zn + CaO
C. Ba + Na₂CO₃
D. Cr + KNO₃
Read more about Activity Series at; brainly.com/question/17469010
