Nancy found that x=1 is one solution to the quadratic equation (x 2)2=a. what is the value of a? -9 -3 3 9
2 answers:
The value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
<h3>What is the solution of equation?</h3>The solution of the quadratic equation is the solution of the variable of the equation, for which the equation satisfies.
Nancy found that x=1 is one solution to the quadratic equation. The quadratic equation is,
For this equation, one solution is <em>x</em>=1. Put this value in the above equation to get the value of <em>a,</em>
Thus, the value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
Learn more about the solution of the equation here;
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Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So
has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater