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3 years ago

5

Squeezy fruit drink is 36% pure orange juice and 64% water, if 1 L of Squeezyfruit drink is mixed with 600 mL of water what is t

he concentration of juice in the new mixture

1 answer:

frez [133]3 years ago

3 0

1 L, or 1000 mL, of the drink contains 360 mL juice. If there is a total of 1600 mL, we have 360/1600=9/40 (or .225) as the concentration of juice.

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Earth is approximately 9.3 × 107 miles from the sun. Saturn is approximately 8.87 × 108 miles from the sun. About how much farth

Lostsunrise [7]

First you get both distances
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8.87 x 108 = 957.96 miles
then you subtract them both
995.1 - 957.96 = 37.14 miles
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A measurement template with a historcal value of 25.500 is measured 27 times and a mean value of 25.301 is recorded. What is the

QveST [7]

Complete Question

A measurement template with a historical value of 25.500 mm is measured 27 times and a mean value of 25.301 mm is recorded. What is the percent bias when the tolerance is +/- 0.3?

Answer:

The percent bias is $B = 33.167 \%$

Step-by-step explanation:

From the question we are told that

The historical value is $S = 25.00 \ mm$

The number of times it is measured is n = 7

The mean value is $\= x = \frac{\sum x_i }{n} = 25.301 \ mm$

The tolerance is $t =\pm 0.3 = 0.3 - (-0.3) = 0.6$

Generally the percent bias is mathematically represented as

$B = 100 * \frac{\= x - \tau }{ t}$

=> $B = 100 * \frac{25.301 - 25.5000 }{0.6}$

=> $B = 33.167 \%$

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2 years ago

If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a

Karolina [17]

Let h = height of the box,
x = side length of the base.

Volume of the box is $V=x^{2} h = 115$ .
So $h = \frac{115}{ x^{2} }$

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
$S = 2( x^{2} + hx + hx) \\ = 2 x^{2} + 4hx \\ = 2 x^{2} + 4( \frac{115}{ x^{2} } )x$
$= 2 x^{2} + \frac{460}{x}$
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

$S' = 4x- \frac{460}{ x^{2} } = 0$
$4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86$
Then $h= \frac{115}{4.86^{2}} = 4.87$
So the box is 4.86 in. wide and 4.87 in. high.

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kifflom [539]

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