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2 years ago

Question is below in picture.

Mathematics

1 answer:

Maurinko [17]2 years ago

6 0

Answer:

C. $\sqrt{89}$ cm

Step-by-step explanation:

First, we can start out by stating that this is a right triangle, since it has a right angle, shown by the marker square in the corner of the triangle. The x part, is called the hypotenuse. When finding the value of the hypotenuse, we use a thing called the Pythagorean Theorem. This theorem is :

a^2 + b^2 = c^2

a is one side length, and b is the other. c is the hypotenuse. To find x, the hypotenuse, we simply plug in the values, and solve.

8^2 + 5^2 = c^2

64 + 25 = c^2

89 = c^2

To get c alone, we do the square root of 89.

$\sqrt{89}$ = c

9.43398113 = c

So, the answer is C. $\sqrt{89}$ cm

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3 years ago

Y=sqrt(x)(8x-5) find the derivative

garri49 [273]

Answer:

$\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

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Step-by-step explanation:

Step 1: Define

$\displaystyle y = \sqrt{x}(8x - 5)$

Step 2: Differentiate

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Product Rule: $\displaystyle y' = \frac{d}{dx}[\sqrt{x}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Rewrite: $\displaystyle y' = \frac{d}{dx}[x^{\frac{1}{2}}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
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Rewrite: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8$
Multiply: $\displaystyle y' = \frac{8x + 5}{2x^{\frac{1}{2}}} + 8\sqrt{x}$
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3 years ago

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Zina [86]

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3 years ago

You plant a tree that is 42 inches tall. After one year, the tree is 47 inches tall. Which expression describes the percent incr

kolezko [41]

Use cross multiplication. 42 inches is your 100%. your fraction would be 42/100
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42 47
----- -----
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(100 * 47) / 42 = X

100 multiplied by 47, then divided by 42, the result is X

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I did this last year, so it may be a little rusty. If im wrong, hopefully someone will correct me, if not, im pretty sure this looks rights. Your methods may also be different. i use cross mulitplication

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3 years ago

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