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2 years ago

Delta Math: Finding Angles (Level 1) 1/5 Full explanation please will give brainlist

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

4 0

Answer:

$m\angle FGC =101\degree$

Step-by-step explanation:

$m\angle CBF = 46\degree$ (Given)

$m\angle FIG = 55\degree$ (Given)

$m\angle IFG = m\angle CBF$ (Corresponding angles)

$\implies m\angle IFG = 46\degree$

$m\angle FGC =m\angle IFG+ m\angle FIG$

(By exterior angle theorem)

$m\angle FGC =46\degree+ 55\degree$

$m\angle FGC =101\degree$

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slava [35]

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Answer:

A: (3x +4)

B: (4x +5y) × (4x -5y)

Step-by-step explanation:

<u>Part A</u>:

Since we know the trinomial is a perfect square, we know the terms of each binomial factor are the square roots of the first and last terms of the trinomial.

9x² +24x +16 = (√(9x²) +√16)² = (3x +4)²

The side of the square is 3x+4.

<u>Part B</u>:

The difference of squares is factored like this:

a²-b² = (a +b)(a -b)

The given area expression is the difference of squares with ...

a = 4x, b = 5y

so, the factorization is ...

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3 years ago

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CaHeK987 [17]

Answer:idk

Step-by-step explanation:

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3 years ago

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kompoz [17]

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3 years ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

V125BC [204]

Answer:

$\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

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Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1\times ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^{12}C_2$

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3 years ago

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Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

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