7. Refer to the diagram. The equilibrium price

21008 rounded to the nearest ten thousands

o-na [289]

The nearest ten thousand is 20,000

6 0

3 years ago

Help meeeeeeeeeeeeeeeeeee <br><br> >_

nignag [31]

Answer:

good news, the second one is relatively easy because it can be factored to (2x+1)(2x-3) which means that number two has solutions of -1/2 and 3/2

but for number one you have to either use the quadratic equation cause I've tried using synthetic division or just use the second equation to derive the first solutions so I tried move the graph up by two units and found that the intercepts are approximately (1+-√2)/2 or 1/2+-1/√2 for 4x^2-4x-1

7 0

3 years ago

Men are believed to have a slightly longer average length of short hospital stays than women; 5.2 days versus 4.5 days respectiv

Georgia [21]

Answer:

Since our calculated value is lower than our critical value, $z_{calc}=2.02$ , we have enough evidence to FAIL to reject the null hypothesis at 1% of singificance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

Step-by-step explanation:

1) Data given and notation

$\bar X_{1}=5.2$ represent the mean for group men

$\bar X_{2}=4.5$ represent the mean for group women

Assuming these values for the remaining data:

$\sigma_{1}=1.2$ represent the population standard deviation for the sample men

$\sigma_{2}=1.5$ represent the population standard deviation for the sample women

$n_{1}=32$ sample size for the group men

$n_{2}=30$ sample size for the group women

z would represent the statistic (variable of interest)

$p_v$ represent the p value

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for men it's higher than the mean for women, the system of hypothesis would be:

H0: $\mu_{1} \leq \mu_{2}$

H1: $\mu_{1} > \mu_{2}$

If we analyze the size for the samples both are higher than 30, and we know the population deviation's, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

We have all in order to replace in formula (1) like this:

$z=\frac{5.2-4.5}{\sqrt{\frac{1.2^2}{32}+\frac{1.5^2}{30}}}=2.02$

4) Find the critical value

In order to find the critical value we need to take in count that we are conducting a right tailed test, so we are looking on the normal standard distribution a value that accumulats 0.01 of the area on the right and 0.99 of the area on the left. We can us excel or a table to find it, for example the code in Excel is:

"=NORM.INV(1-0.01,0,1)", and we got $z_{critical}=2.33$

5) Statistical decision

Since our calculated value is lower than our critical value, $z_{calc}=2.02$ , we have enough evidence to FAIL to reject the null hypothesis at 1% of significance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

6 0

3 years ago

Each flower has a specific price. One tulip, one daisy, and 2 mums cost $4.20. On tulip, two daisies and one mum cost $3.80. Two

sineoko [7]

Answer:

The answer to your question is $5.60

Step-by-step explanation:

1 tulip + 1 daisy + 2 mums = $4.20 (1)

1 tulip + 2 daisies + 1 mum = $ 3.80 (2)

2 tulips + 2 mums = $4.80 (3)

1 tulip + 3 daisies + 2 mums = ?

tulip = t daisy = d mum = m

Process

1.- Find the price of each flower using system of equations

Solve equation 3 for tulip

2t = 4.80 - 2 m divide by 2 (4)

t = 2.40 - 1m

2.- Substitute equation 4 in equation 1 and 2

(2.4 - 1m) + 1 d + 2 m = 4.2

(2.4 - 1m) + 2d + 1 m = 3.8

3.- Simplify and solve for each flower

2.4 - 1m + 1d + 2m = 4.2

1d + 1m = 4.2 - 2.4

1d + 1m = 1.8 Equation (5)

2.4 - 1m + 2d + 1m = 3.8

2d = 3.8 - 2.4

2d = 1.4

d = 1.4/2

1d = 0.7

4.- Substitue d in equation 5

1(0.7) + 1m = 1.8

0.7 + 1m = 1.8

1m = 1.8 - 0.7

1m = 1.1

5.- Subtitute m in equation 4

1t = 2.40 - 1(1.1)

1t = 2.40 - 1.1

1t = 1.3

6.- Result

1 tulip + 3 daisies + 2 mums cost = 1.3 + 3(0.7) + 2(1.1)

= 1.3 + 2.1 + 2.2

= $5.6

8 0

3 years ago

If a tellemarketer made 200 phone calls and 35 customers signed up what is the relative frequency of getting a customer and not

Snezhnost [94]

Answer:

82.5% and 17.5%

Step-by-step explanation:

The telemarketer made 200 phone calls and only 35 people signed up. Therefore, we need to find the amount of people who didnt.

200 - 35 = 165

165 people did not sign up.

This meants that the frequency of getting a customer is 35/200 and not is 165/200. In percentages,

The relative frequency of not getting a customer is 82.5%

The relative frequency of getting a customer is 17.5%

6 0

3 years ago