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2 years ago

14

During taylor's experiment, which piece of data would be qualitative?

1 answer:

Reptile [31]2 years ago

5 0

There isn't any piece of data during Taylor's experiment which can be taken as qualitative. Thus, correct choice is: Option D: None are qualitative.

<h3>What is qualitative data?</h3>

Qualitative data tells about the quality or characteristic. It is tough to express it numerically or not at all expressible numerically. They are usually catagorical.

In contrast, there is quantitative data which can be expressed numerically.

The problem is missing its option, which are:

mass of the cars
degree of the ramp incline
time in seconds
none are qualitative

Mass can be measured (in kgs, grams etc), degree of inclination can be measured (in radians, degree etc), time can be measured (in seconds, minutes etc).

Thus, there isn't any piece of data during Taylor's experiment which can be taken as qualitative. Thus, correct choice is: Option D: None are qualitative.

Learn more about qualitative and quantitative data here:

brainly.com/question/12929865

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solve for x and round to the nearest tenth. this is geometry. I will mark Brainliest. please help <3

Amiraneli [1.4K]

Answer:

x= 41.8°

Step-by-step explanation:

use inverse trig to find x.

$sin^{-1}$ ( $\frac{4}{6}$ )=x

type this into your calculator. (make sure the mode on your calculator is degree or it won't work)

x= 41.8

Hope This Helps:)

brainliest please

5 0

2 years ago

Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct

Nana76 [90]

Answer:

$Fx=\frac{5\pm\sqrt{25+24} }{6}$

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

$ax^2+bx+c$

Where:

$a\neq 0$

The roots of this equation can be found using the quadratic formula, which is given by:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

So:

$y(x)=3x^2-5x-2=0$

As you can see, in this case:

$a=3\\b=-5\\c=-2$

Using the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}$

Therefore, the answer is:

$Fx=\frac{5\pm\sqrt{25+24} }{6}$

4 0

3 years ago

(4+3) 2 +5= <br> pls tell me i have no idea

horrorfan [7]

Answer:

19

Step-by-step explanation:

(4+3)2+5=

7(2)+5=

14+5=

19

4 0

3 years ago

zvonat [6]

Answer:

$x$

Step-by-step explanation:

<u><em>The correct question is</em></u>

Solve. −3/5x+1/5>7/20 Drag and drop a number or symbol into each box to show the solution

we have

$-\frac{3}{5}x+\frac{1}{5} >\frac{7}{20}$

Solve for x

Multiply by 20 both sides

$-12x+4 >7$

subtract 4 both sides

$-12x >7-4$

$-12x >3$

divide by -12 both sides

Remember that when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x$

simplify

$x$

6 0

3 years ago

Read 2 more answers

An integer is 8 more than 5 times another. If the product of the two integers is 36, then find the integers

Harman [31]

Answer:

see below

Step-by-step explanation:

1st: x

2nd: 5x + 8

x(5x + 8) = 36

5x² + 8x = 36

5x² + 8x - 36 = 0

(x - 2)(5x + 18) = 0

(x - 2) = 0

x - 2 = 0

x = 2

1st: x = 2

2nd: 5x + 8 = 5(2) + 8 = 18

(5x + 18) = 0

5x + 18 = 0

5x = -18

x = -3.6

1st: x = -3.6

2nd: 5x + 8 = 5(-3.6) + 8 = -18 + 8 = -10

7 0

3 years ago