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Cloud [144]
2 years ago
7

If f(x)f(x) is an exponential function where f(-1)=5f(−1)=5 and f(7)=32f(7)=32, then find the value of f(4)f(4), to the nearest

hundredth
Mathematics
1 answer:
Whitepunk [10]2 years ago
5 0

Using an exponential function, it is found that the value of the function when x = 4 is of f(4) = 15.95.

<h3>What is an exponential function?</h3>

It is modeled by:

y = ab^x

In which:

  • a is the initial value.
  • b is the rate of change, as a decimal.

In this problem, we have that f(-1)=5, hence:

5 = ab^{-1}

\frac{a}{b} = 5

a = 5b

We also have that f(7)=32, hence:

32 = ab^7

Since a = 5b:

5b^8 = 32

b = \sqrt[8]{\frac{32}{5}}

b = 1.2612.

a = 5b = 5 x 1.2612 = 6.306.

Hence the function is given by:

y = 6.306(1.2612)^x

Then, when x = 4, we have that:

y = 6.306(1.2612)^4 = 15.95

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

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