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Luda [366]
2 years ago
7

Evaluate the expression for x = 6.

Mathematics
1 answer:
kifflom [539]2 years ago
4 0
C or A for x =6. ……………………………….
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2 Which of the following polynomials is not written in standard form?
Varvara68 [4.7K]

Answer:

3

Step-by-step explanation:

Standard form is written in the order of the exponent <em>on</em><em> </em><em>a</em><em> </em><em>variable</em> from highest to lowest.

#1 exponents go 2, 1 , then zero. So, this is standard form.

#2 exponents go 2 then zero, so this is standard form.

#3 exponents go 1 then 2 then zero, so this is <em><u>not</u></em> in standard form.

#4 exponents go 3 to 2 to 1, so this is still in standard form.

hope this helps!

8 0
3 years ago
Find the greatest common factor of 15x^2 y^3 and -20x^3yz
maxonik [38]
5x^2y

5 is the largest number to go in evenly. And the terms are limited to those. 
6 0
3 years ago
5. Marie buys 2 pounds of turkey and 1 pounds of ham. She pays a total of $20,
NARA [144]

Answer:Let t = cost per pound of turkey

Let h = cost per pound of ham

 

4t + 2h = 30

t = h - 1.5

 

substitute h-1.5 in place of t in 1st equation

 

4(h-1.5) + 2h = 30

4h - 6 + 2h = 30

6h - 6 = 30

6h = 36

h = 6

 

t = h-1.5 = 4.5

 

1 pound of turkey costs $4.50

1 pound of ham costs    $6.00

                                ----------

cost of 1 pound each  $10.50

Step-by-step explanation:

8 0
2 years ago
Solve the equation using the quadratic formula. Enter each solution in simplest form.
sergeinik [125]

For this case we have the following quadratic equation:

x ^ 2-4x + 23 = 0

The solutions will be given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Where:

a = 1\\b = -4\\c = 23

Substituting the values we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}

We have two roots:

x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}

ANswer:

x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}

6 0
4 years ago
Solve for x. Explain the steps taken to find the solution.<br><br> 3/2 + 3x/5 = 9/2 4x/5
Iteru [2.4K]

Answer:

46

i just got it right

7 0
3 years ago
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