Answer:
30th term is
9(30+3) =270+27=297
to find the first term which is larger than 100
9(n+3) =100
9n=100-27
9n=73
n=73÷9
=8.1
so when n is>8.1 all the terms will be larger than 100 and the first term will be 9 since n can't be fraction as it's an ordinary number
so it's 9th
9(9+3) =81+27=108
the first four terms are
9(1+3) =36
9(2+3) =45
9(3+3) =81
9(4+3) =63
Step-by-step explanation:
n(n-1)
the first four terms are
1(1-1) =0
2(2-1) =2
3(3-1) =6
4(4-1) =12
the 10th term is 10(10-1) =90
to find weather 51 is a term or not
n(n-1) =51
n^2-n-51=0
1-4×1×-51=1+204=205
so it's roots will be fraction
so it's not from its terms because n will
be fraction
to find the term 182
n(n-1) =182
n^2-n-182=0
(n-14) (n+13)=0
so it's the term 14th because n can't be negative
Hello!
You first have to find the scale factor between the triangles
To do this you divide the new side length by the old one
9 / 6 = 1.5
They multiplied the smaller triangle by 1.5 to get the bigger one
Do this to find the missing length
8 * 1.5 = 12
The answer is 12
Hope this helps!
The last one (0, -3) because it doesn’t move to the left/right, only up/ down.
The question is an illustration of selection (or combination)
The number of lock combination is 343
The given parameters are:
<em />
<em> --- the number of digits to select from</em>
<em />
<em> --- the number of digits the lock uses</em>
<em />
Because the digits can be repeated, the number of lock combinations is:
So, we have:
Hence, the number of lock combination is 343
Read more about combinations at:
brainly.com/question/15301090
