Question

Claim: The mean pulse rate​ (in beats per​ minute) of adult males is equal to 69 bpm. For a random sample of 147 adult​ males, the mean pulse rate is 69.5 bpm and the standard deviation is 11.2 bpm. Find the value of the test statistic.

Answer 1

Answer:

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)  

And replacing we got:

$t=\frac{69.5-69}{\frac{11.2}{\sqrt{147}}}=0.541$  

Step-by-step explanation:

Information given

$\bar X=69.5$ represent the sample mean    

$s=11.2$ represent the sample standard deviation

$n=69$ sample size  

$\mu_o =69$ represent the value that we want to test

t would represent the statistic (variable of interest)  

Hypothesis to test

We want to check if the true mean is 69, the system of hypothesis would be:  

Null hypothesis:$\mu =69$  

Alternative hypothesis:$\mu \neq 69$  

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)  

And replacing we got:

$t=\frac{69.5-69}{\frac{11.2}{\sqrt{147}}}=0.541$