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2 years ago

Roberto ran 3/8 laps , juliette ran 2/3 laps and cora ran 1 1/4 laps. how many did they run together

Mathematics

1 answer:

ELEN [110]2 years ago

3 0

Answer:

3 19/24

Step-by-step explanation:

$\frac{3}{8} + \frac{2}{3} + \frac{11}{4} = \frac{9 + 16 + 66}{24} = \frac{91}{24} = 3 \frac{19}{24 }$

hope it helps

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A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe

Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

$Volume=\frac{1}{2} (b_{1}+4+2x)h X H$

$Volume=\frac{1}{2} (4+4+2x)h X 16$

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

$V=64h+16h(\frac{h}{4})$

$V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}$

h=3m,

dV/dt=25cm/min=0.25 m/min

$0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}$

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0

4 years ago

Please help i dont understand this at all

tamaranim1 [39]

I have no idea but I googled and I got 0.6 I hope this helps!

5 0

4 years ago

What is 3/18 simplified

trasher [3.6K]

All you have to do is divide the numerator and the denominator by 3 and you get your answer which is 1/6

4 0

3 years ago

Read 2 more answers

Please help! Help is appreciated! :)

-Dominant- [34]

Your answer to the question is A

4 0

4 years ago

Write the product in simplest form: 3w^4 * (-5w^2)

Grace [21]

$3w^{4} (-5w^{2} ) = -15w^{6}$

I think this is what you want? When multiplying with exponents, you either add or multiply the exponents.

When you multiply the exponent:

(x²)³ = $x^{6}$

$(3x^{4} )^{2}$ = 9 $x^{8}$

When you add the exponents:

(x²)(x³) = $x^{5}$

(x²)(x²) = $x^{4}$

$(x^{4} )(x^{3} ) = x^{7}$

5 0

4 years ago