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kotegsom [21]
2 years ago
12

Roberto ran 3/8 laps , juliette ran 2/3 laps and cora ran 1 1/4 laps. how many did they run together

Mathematics
1 answer:
ELEN [110]2 years ago
3 0

Answer:

3 19/24

Step-by-step explanation:

\frac{3}{8}  +  \frac{2}{3}  +  \frac{11}{4}  =  \frac{9 + 16 + 66}{24}  =  \frac{91}{24}  = 3 \frac{19}{24 }

hope it helps

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A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

Volume=\frac{1}{2} (b_{1}+4+2x)h X H

Volume=\frac{1}{2} (4+4+2x)h X 16

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0
4 years ago
Please help i dont understand this at all
tamaranim1 [39]
I have no idea but I googled and I got 0.6 I hope this helps!
5 0
4 years ago
What is 3/18 simplified
trasher [3.6K]
All you have to do is divide the numerator and the denominator by 3 and you get your answer which is 1/6
4 0
3 years ago
Read 2 more answers
Please help! Help is appreciated! :)
-Dominant- [34]
Your answer to the question is A
4 0
4 years ago
Write the product in simplest form: 3w^4 * (-5w^2)
Grace [21]

3w^{4} (-5w^{2} ) = -15w^{6}

I think this is what you want? When multiplying with exponents, you either add or multiply the exponents.

When you multiply the exponent:

(x²)³ = x^{6}

(3x^{4} )^{2} = 9x^{8}

When you add the exponents:

(x²)(x³) = x^{5}

(x²)(x²) = x^{4}

(x^{4} )(x^{3} ) = x^{7}

5 0
4 years ago
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