Answer:
16k^2 + 62k + 21
Step-by-step explanation:
We can distribute:
(8k + 3)(2k + 7)
(8k)(2k) + (8k)7 + 3(2k) + 3(7)
Now, we can simplify:
16k^2 + 56k + 6k + 21
16k^2 + 62k + 21
Answer:
it is not true
Step-by-step explanation:
Answer:
identity
Step-by-step explanation:
Answer:

Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that
and also
.
In order to prove that ∆ABC
∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:

Answer:
cba is a secant, although the point barely goes through c
Step-by-step explanation:
a secant is a straight line that intersects a curve at 2 or more points. :)