Answer: 60 yd
Step-by-step explanation:
Here: subdivided into 3 smaller pens (2w + w + w) extra widths for separation purposes (3 smaller pens)
180 yards of fencing material
180yd = 2L + 4w
180dy = 2*60 + 4w
60dy = 4w
w = 15yd, how wide can the rectangle can be with L = 60yd
Answer:
84? Not sure but pretty sure
Step-by-step explanation:
In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.
If 90° and reflex turns are allowed, then the number substantially increases.
Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.
2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.
Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.
Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.
This is a conversion problem. We know that 1 mile is 5280 feet, right? Since Ellie lives 2 miles, and two is double of 1, we just take 5280 and multiply that by two (or add it twice) to find how many feet is between Ellie's house and school. 5280 x 2 = 10560 (you get the same answer if you add 5280 twice). Therefore, 10560 feet lies between Ellie's house and school.
Answer:
A. 12
Step-by-step explanation:
-2*-1=2*6=12
plz mark brainliest
