I believe that Cell a is most likely in G1 phase.
The G1 phase, or the gap 1 phase, is the first of four phases of the cell cycle that takes place in eukaryotic cell division. In this part of interphase, the cell synthesizes mRNA and proteins in preparation for subsequent steps leading to mitosis. The phase ends when the cell moves into the S phase of interphase.
Answer:
Option-C
Explanation:
A pulse-chase experiment which is used to study the cellular process taking place in the cells. This uses the labelled molecule which is incorporated into the cellular pathway and then the unlabeled molecules are used over time to determine how much time is required by the unlabeled molecule to replace the labelled molecule.
In the given question, the pancreatic cell which secretes the digestive enzyme known as the acinar cell is labelled with the leucine and then used unlabeled leucine.
When observed after three hours, the black spots will appear on the exterior of the cell as the protein has been synthesised by the ER and now has been secreted from the cell.
Thus, Option-C is the correct answer.
The question is incomplete. The complete question is:
Question: What is the expected percent change in the DNA content of a typical eukaryotic cell as it progresses through the cell cycle from the start of the G1 phase to the end of the G2 phase
a. -100%
b. -50%
c. +50%
d. +100%
Answer:
d. +100%
Explanation:
S phase comes between G1 and G2 phases of the interphase of a cell cycle. S phase of interphase includes replication of DNA. The process of DNA replication doubles the amount of DNA present in the cell. The newly synthesized DNA is accommodated in the sister chromatids of chromosomes. Therefore, a cell with 2C DNA in the G1 phase would have 4C DNA at the end of the G2 phase. So, there is a +100% increase in the DNA content of a cell as it proceeds from G1 to the end of the G2 phase.
The goal was to orbit a spacecraft around the Earth. It has people in it. So the answer is B.
