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shutvik [7]
3 years ago
15

Which expression is equivalent to P/6 +(q+8)

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0
The awnser is c (p6+q) +8
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If a = 12 and b= 2. solve ab + ( 3a - 8b)​
lorasvet [3.4K]

Answer:

44

Step-by-step explanation:

3 0
3 years ago
un campo de futbol tiene 100m de largo y 60m de ancho¿ Cuales son la longitud y la anchura del campo?
Alex Ar [27]

Answer:

328 pies de largo

196.8 pies de ancho

Step-by-step explanation:

Ya que las medidas dadas estan en metros, podemos usar esas medidas para calcular la longitud y anchura en pies.

100 metros de largo.

60 metros de ancho.

Si sabemos que 1m es igual a 3,28 pies, simplemente tenemos que multiplicar las medidas en metros por 3.28 y nos va dar la medida del campo en pies.

100 * 3.28 = 328 pies de largo

60 * 3.28 = 196.8 pies de ancho

8 0
3 years ago
Can someone help me with this question?
Morgarella [4.7K]

Answer:

I got 15 and 12

PLZ CORRECT ME IF I AM WRONG PLEASE AND THanK YOU

Step-by-step explanation:

3 0
3 years ago
Identify the domain and range of following relation {(3,7),(3,8),(3,-2),(3,4)(3,1)
PSYCHO15rus [73]
The domain is the x-values. So domain is 3. Range is y-values. So range is -2, 1, 4,7, and 8. When writing either range or domain don't repeat numbers ,(example: domain is 3,3,3: wrong) and try putting the numbers from least to greatest.
5 0
3 years ago
Find the limit............​
liubo4ka [24]

Answer: -\frac{9}{x^2}

====================================================

Work Shown:

\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9}{x+\Delta x} - \frac{9}{x}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9x}{x(x+\Delta x)} - \frac{9(x+\Delta x)}{x(x+\Delta x)}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{\frac{9x-9(x+\Delta x)}{x(x+\Delta x)}}{\Delta x}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{9x-9x-9\Delta x}{x\Delta x(x+\Delta x)}\\\\\\

\displaystyle \lim_{\Delta x \to 0^{+}} \frac{-9\Delta x}{x\Delta x(x+\Delta x)}\\\\\\\displaystyle \lim_{\Delta x \to 0^{+}} \frac{-9}{x(x+\Delta x)}\\\\\\\displaystyle \frac{-9}{x(x+0)}\\\\\\\displaystyle -\frac{9}{x^2}\\\\\\

The trick here is to first simplify the expression so that the \Delta x term in the very lower denominator cancels out. This is to avoid dividing by zero. Once this division by zero error is avoided, we can replace the delta x term with 0 and evaluate the limit as \Delta x approaches 0 from the right or positive direction.

5 0
3 years ago
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