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3 years ago

-3x² - 4x – 8=0 Does anyone know how to solve this?

Mathematics

1 answer:

sveta [45]3 years ago

7 0

Answer:

That is a quadratic equation.

It can be solved by using the quadratic formula:

x = (-b +-sqr root b^2 -4*a*c) / 2 *a

In this equation a = -3

b = -4 and c = -8

x = (--4 +- sqr root (-4^2 - 4 * -3 * -8)) / (2 * -3)

x = (4 +- sqr root (16 -96)) / -6

x = 4 +- sqr root (-80) / -6

x1 = (4 +8.94427191 * i) / -6

x2 =(4 -8.94427191 * i) / -6

Remember that "i" is the square root of minus 1.

Step-by-step explanation:

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Read 2 more answers

Help ASAP!! Using the graphed function above, find the following

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Maximum: 1, Minimum: -3, Midline y = -1, Amplitude = 4, Period = $\pi$ , Frequency $\displaystyle =\frac{1}{\pi}$ , equation : $f(x)=-4cos(2x)+1$

Step-by-step explanation:

Sinusoid Functions

It refers to the oscillating functions like the sine or cosine which range from a minimum and maximum value periodically.

The graph shown can give us all the information we need to answer these questions:

Maximum: 1

Minimum: -3

The midline goes through the center value (mean) of the max and min values, i.e.

Equation of the midline:

$\displaystyle y=\frac{1-3}{2}=-1$

Amplitude is the difference between the maximum and minimum values

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The period is the time it takes to complete a cycle. We can see the minimum value is first reached at x=0 and next at $x=\pi$

Thus the period is

$T=\pi$

The frequency is the reciprocal of the period:

$\displaystyle f=\frac{1}{T}=\frac{1}{\pi}$

The angular frequency is

$\displaystyle w=2\pi f=\frac{2\pi }{\pi}=2$

The equation of the function is a negative cosine (since it starts at the minimum) or a shifted sine or cosine. We'll choose the negative cosine, knowing all the parameters:

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Step-by-step explanation:

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