Answer:
There are no true solutions to the equation.
Step-by-step explanation:
<u><em>The correct equation is</em></u>

Solve for y
squared both sides






<em>Verify</em>
substitute the value of y in the original expression

----> is not true
therefore
There are no true solutions to the equation.
Answer:
3.49
Step-by-step explanation:
B = 5.5-2.01 = 3.49
have a great day!
Answer:
y=1/2x+3.5
Step-by-step explanation:
this one was a bit trickier than the previous one, but i think that that answer is correct. i did the same thing i did to solve your last problem, solved for the slope, and then made a number line and marked the points given, drew a line through the two points, and found where the line intercepted the y axis.
Answer:
<h3>They fought is very major Americans battle war ll</h3><h3>Between 400,000 and 500,000 Hispanic Americans served in the US armed forces</h3><h3> during world War II out of total of</h3><h3>16,000,000 constituting 3.1% to 3.2% of the US Armed forces </h3><h2>I hope you like it </h2><h2>Please give me a brainliest answer </h2>
Answer:
5.78% probability that exactly 2 of them use their smartphones in meetings or classes.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they use their smarthphone in meetings or classes, or they do not. The probability of an adult using their smartphone on meetings or classes is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
63% use them in meetings or classes.
This means that 
7 adult smartphone users are randomly selected
This means that 
Find the probability that exactly 2 of them use their smartphones in meetings or classes.
This is P(X = 2).


5.78% probability that exactly 2 of them use their smartphones in meetings or classes.