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erastova [34]
3 years ago
14

In the image shown, line n is a transversal cutting parallel lines l and m. ∠1 = 3x + 18 ∠7 = 2x + 39 What is the measure of ∠7?

A) 79° B) 81° C) 83° D) 86°

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
7 0

Answer:

b balty brings

Step-by-step explanation:

wel3 years ago
4 0

Answer:

B) 81°

Step-by-step explanation:

Given:

From the figure given below,

∠1 = 3x + 18

∠7 = 2x + 39

∠1  and ∠7 are a pair of exterior alternate angles. For two parallel lines l and m, cut by a transversal n, the pair of exterior alternate angles are congruent to each other.

Therefore, the angles 1 and 7 are congruent to each other. This gives,

∠1  ≅ ∠7

3x+18=2x+39\\\\3x-2x=39-18\\\\x=21

Therefore, the value of 'x' is 21.

Now, the measure of angle 7 can be calculated by plugging in the value of 'x' in the expression for angle 7. This gives,

\angle 7 = 2x + 39\\\\\angle 7 =2\times 21+39\\\\\angle 7 =42+29\\\\\angle 7 =81\°

Therefore, the correct option is option (B).

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lidiya [134]

Answer:

4:1

Step-by-step explanation:

just divide by the highest numbe 2 in this case

6 0
3 years ago
Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!
Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34  

Step-by-step explanation:

Given:  

2x-3y=12  

To Find:  

Equation of line passing through ( 16, -7) and is perpendicular to the line  

2x-3y=12  

Solution:  

2x-3y=12 ...........Given  

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx+c  

Where m =slope  

We get  

Slope = m1 = \dfrac{2}{3}  

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}  

Now the equation of line in slope point form given by  

(y-y_{1})=m(x-x_{1})  

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,  

(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line  

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line  2x-3y=12 is

3x+2y=34  

3 0
3 years ago
Which wind belt starts at the horse latitudes and moves toward the poles?
kvasek [131]

Answer:

The prevailing westerlies.

Step-by-step explanation:

The prevailing westerlies are found between 30 (horse latitudes) and 60 degrees latitude. They come from the high-pressure areas in the horse latitudes and go towards the poles.

4 0
4 years ago
Solve the following equations x1/3=2 <br> Y-2=9<br> (2s)1/2=9<br> 2n-1=16
Nookie1986 [14]

x \times  \frac{1}{3}  = 2 \\  =  > x = 2 \times 3 \\  =  > x = 6

y - 2 = 9 \\  =  > y = 9 + 2 = 11

(2s) \frac{1}{2}  = 9 \\  =  > s = 9

2n - 1 = 16 \\  =  > 2n = 16 + 1 \\  =  > 2n = 17 \\  =  > n =  \frac{17}{2}  = 8.5

<h3>The answers are :</h3><h3>x = 6</h3><h3>y = 11</h3><h3>s = 9</h3><h3>n = 8.5</h3><h3>Hope it helps!</h3><h3 />

7 0
3 years ago
the stove and the freezer weigh at least 260kg. the stove weighs 115 kg. How much would the freezer weigh?
Aleks [24]
About 145 I gonna guess I dont know if that's right
7 0
3 years ago
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