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prohojiy [21]
2 years ago
6

A right pyramid with a regular hexagon base has a base edge length of 4 ft and a height of 10 ft. wy represents the . if the are

a of an equilateral triangle with sides of 4 ft is 4startroot 3 endroot square feet, then the area of the regular hexagon base is startroot 3 endroot square feet. the volume is startroot 3 endroot .
Mathematics
1 answer:
Alchen [17]2 years ago
8 0

The volume of the right pyramid with the given properties is 80√3 cubic volume

<h3>How to determine the volume?</h3>

The given parameters are:

  • Area of equilateral triangle = 4√3
  • Height = 10Base length = 4 ft

Start by calculating the base area using:

Base area = 6 * Area of equilateral triangle

So, we have:

Base area = 6 * 4√3

Evaluate

Base area = 24√3

The volume of the pyramid is:

Volume = 1/3 * Base area * Height

So, we have:

Volume = 1/3 * 24√3 * 10

Evaluate

Volume = 80√3

Hence, the volume of the right pyramid is 80√3 cubic volume

Read more about volume at:

brainly.com/question/1972490

#SPJ4

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Q.The rectangular front windshield of the bus has the length of 1.5√3 m and the width of 1.5 m . The wipers are attached to the
galina1969 [7]

Answer:

Area covered by wiper=area of arc(A0D)+area of traingleAOB+area of arc(BOC)

We know AO and OB are wipers,whose lengths are 1.5

In ∆ABC

AB^2+BC^2=AC^2

(1.5√3)^2+(1.5)^2=(AC)^2

2.25×3+2.25=(AC)^2

2.25×4=AC^2

AC=3

Also AO=1.5

similarly using Pythagoras theorem in ∆OBC

we get

OC=1.5

this shows that point O is the bisector of diagonal AC

so,AO=OC

also from property of rectangle we know that, diagonal bisects each other equally

so,O will also be the bisector of diagonal BD

hence OB=OD=1.5

AC=BD (property of triangle)

AC/2=BD/2

OB=OC,hence OB=OC=OD=OA=1.5=AD=BC

Hence OAD will be an equilateral triangle

so

angle OAD=60

similarly angleOBC=60

area of sector=angle of that sector ×area of circle/360

area of arc(AOD)+arc(BOC)=60/360 ×3.14 ×1.5×1.5 +60/360 ×3.14×1.5×1.5

=2×(60/360)×1.5×1.5

area of triangleAOB=area of rectangle/4 (diagonal divides the rectangle in 4 equal parts)

area of triangle=1.5×1.5√3/4

=>1.5×2.6/4=3.90/4

=0.975 or 0.98(approx)

Area covered by wiper=.98+2×60/360 ×3.14×1.5×1.5

=.98+0.75×3.14=2.35+0.97

=2.35+.98

Percentage of area of windshield covered by wiper=3.3×100/3.9=84.61

hence percentage of area of windshield covered by wiper is 85percent(approx)

plz mark brainlest

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Answer: 94.8 % (approx)

Step-by-step explanation:

Let the total household in the U.S is x,

⇒ The total household who did not have a telephone in 1960 = 21.5 % of x

= 0.215 x

According to the question,

The total household who do not have a telephone in 1990 = 75.8 % less than the household in 1960 who did not have the cell phone,

= (100-75.8)% of 0.215x

= 24.2 % of 0.215x

= 0.05203x,

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Hence, the percentage of household who has a telephone in 1990

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= 94.797\%\approx 94.8\%

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Step-by-step explanation:

C=2 \pi r

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