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prohojiy [21]
2 years ago
6

A right pyramid with a regular hexagon base has a base edge length of 4 ft and a height of 10 ft. wy represents the . if the are

a of an equilateral triangle with sides of 4 ft is 4startroot 3 endroot square feet, then the area of the regular hexagon base is startroot 3 endroot square feet. the volume is startroot 3 endroot .
Mathematics
1 answer:
Alchen [17]2 years ago
8 0

The volume of the right pyramid with the given properties is 80√3 cubic volume

<h3>How to determine the volume?</h3>

The given parameters are:

  • Area of equilateral triangle = 4√3
  • Height = 10Base length = 4 ft

Start by calculating the base area using:

Base area = 6 * Area of equilateral triangle

So, we have:

Base area = 6 * 4√3

Evaluate

Base area = 24√3

The volume of the pyramid is:

Volume = 1/3 * Base area * Height

So, we have:

Volume = 1/3 * 24√3 * 10

Evaluate

Volume = 80√3

Hence, the volume of the right pyramid is 80√3 cubic volume

Read more about volume at:

brainly.com/question/1972490

#SPJ4

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