Let w= the length of the side perpendicular to the barn
300-2w= length of the side parallel to the barn
A=w(300-2w)
A=-2w^2+300w
The formula for the w-value of maximum is:
=-b/2a
thus our value will be:
300/4
=75
and
300-2(75)
=150
thus the dimensions to maximize the area is 75 by 150
Answer:
x=42
Step-by-step explanation:
i don't know how to explain it??
not good at explaining things
Cool dude that’s very cool
Answer:
$.999 for 1 pound
Step-by-step explanation:
If you divided both sides by 10. So 10/10= 1. 9.99/10= 0.999
0.2+ 0.05 My response is to short..sooooo hope u like my answer
