Answer:
The correct answer is - XTXt
Explanation:
In the question, it is given that in cats the coat color is an X-linked trait that shows incomplete dominance if present in heterozygous condition.
The allele for yellow allele = XT (it is dominant allele)
The allele for black coat = Xt (it is recessive allele)
The amle cat can not show the heterozygous condition or tortoise coat as they have only one X chromosome so they will be either yellow coat cats or black coat cats.
In female cats the tortoise coat will show when the both allele present together: XTXt due to their incomplete dominance.
Answer:
A. by breaking off a phosphate molecule from itself structure
Answer: Mutualism
Explanation: When two animals help one another in a beneficial way for both parties then it is considered mutualism.
Explanation:
Cells in each germ layer differentiate into tissues and embryonic organs The ectoderm gives rise to the nervous system and the epidermis, among other tissues
That was the picture, here is the math. Rather than computing all the individual probabilities then multiplying them out, I prefer to compute the probability distribution of each generation and pass it along that way.
The grandfather's probability of being Tt is 2/3. *If he is Tt* each of his offspring (2a and 2b) has a 1/2 probability of being Tt as well. So overall, the probability for each of his offspring being Tt is 2/3 * 1/2 = 1/3.
The offspring are independent events (one would hope) so the probability of both his offspring 2a and 2b being Tt is 1/3 * 1/3 = 1/9.
If 2a is Tt, 2a and TT spouse have a 1/2 probability of producing a Tt offspring. The same argument applies to 2b. The probability that 2a and 2b produce Tt offspring is 1/2 * 1/2 = 1/4. But the probability that 2a and 2b were Tt is 1/9 as calculated above. So the probability that 3a and 3b are both Tt is 1/4 * 1/9 = 1/36. So there is a 1/36 chance that 3a and 3b both are carriers.
If 3a and 3b have a child and if they are both Tt carriers, the probability that they will have a tt child is 1/4. The probability that 3a and 3b are both carriers is 1/36. So to obtain the probability of a tt child is 1/4 * 1/36 = 1/144.
I hope that this is the answer that you were looking for and it has helped you.
