Question

A painting company will paint this wall of a building. The owner gives him the following dimensions.

Answer 1

The given area of the $52\frac{1}{2}$ ft. by 33 ft. wall less the areas of the Windows and the Door give the area of the painted part of the wall as  $\underline{1642\frac{9}{16}}$ ft.²

How can the area of the painted part be calculated?

The area of the painted part of the wall is $\underline{1642\frac{9}{16}}$ ft.²

The given dimensions of the wall are;

The width of the wall = $52\frac{1}{2}$ ft.

The height of the wall = 33 ft.

The painted area = Area of the wall - (Area of the widows + The door)

Which gives;

$52\frac{1}{2} \times 33 - \left(6\frac{1}{4} \times 5\frac{3}{4} + 3\frac{1}{8} \times 4 + 9\frac{1}{2} + 4 \times 8 \right) = \mathbf{ 1642 \frac{9}{16}}$

The area of the painted part of the wall is $\underline{1642\frac{9}{16}}$ ft.²

Learn more about the area of a rectangle here:

brainly.com/question/18101587