Ask question

Ask question

All categories

soldier1979 [14.2K]

3 years ago

10

If a 40-m rope is cut into two pieces in the ratio 3:5 how long is each piece

1 answer:

Vinvika [58]3 years ago

6 0

3:5.....added = 8

3/8(40) = 120/8 = 15 m <== one piece
5/8(40) = 200/8 = 25 m <== the other piece

You might be interested in

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago

4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o

harina [27]

Answer:

$y=3e^{-4t}$

Step-by-step explanation:

$y''+5y'+4y=0$

Applying the Laplace transform:

$\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0$

With the formulas:

$\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)$

$\mathcal{L}[y']=s\mathcal{L}[y]-y(0)$

$\mathcal{L}[x]=L$

$s^2L-3s+5sL-3+4L=0$

Solving for $L$

$L(s^2+5s+4)=3s+3$

$L=\frac{3s+3}{s^2+5s+4}$

$L=\frac{3(s+1)}{(s+1)(s+4)}$

$L=\frac3{s+4}$

Apply the inverse Laplace transform with this formula:

$\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}$

$y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}$

7 0

2 years ago

When completed, the Great Pyramid of Giza was 481 feet in height. Lindy constructed a model of the pyramid using the scale 1

Ivan

English plz then I can answer it lol

5 0

3 years ago

Find the measure for angle DEF

nadezda [96]

Answer:

Step-by-step explanation:

∠DEF=90-58.2=31.8°

4 0

2 years ago

Read 2 more answers

Please help me with this and explain how u did it step by step

joja [24]

The domain of the third piece of the graph is contained in interval <u>B. (12, 20)</u>.

<h3>What is the domain of a graph?</h3>

The domain of a graph consists of all the input values shown on the x-axis.

The input values (domain) are shown on the x-axis, unlike the range, whose output values are shown on the y-axis.

Therefore, the domain comprises the independent variables or values, which can be determined using the function, y = f(x).

Thus, the domain of the third piece of the graph can be determined in interval <u>B. (12, 20)</u>.

Learn more about domain and range at brainly.com/question/10197594 and brainly.com/question/2264373

#SPJ1

6 0

1 year ago