We have to solve this equation:
Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:
Now we can find the roots of the quadratic polynomial as:
Then, the solutions to the equation are:
x = 0
x = 3 - √3
x = 3 + √3
Answer:
X=2
Step-by-step explanation:
-3, -2.5, -3/4, 1/4, 3.1, 16/5, 6. I can’t see the other numbers, so it’s just these
Answer:
1. b
2. d
3. a
4. A
Step-by-step explanation: