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IRISSAK [1]
2 years ago
6

Discuss the advantages and disadvantages of supporting links to files that cross mount points (that is, the file link refers to

a file that is stored in a different volume).
Computers and Technology
1 answer:
Rudiy272 years ago
3 0

Advantage - greater transparency; user doesn't need to be aware of mount points / link creation

Disadvantage - file system containing the link may be mounted while the file system containing the target file may not be; resulting in a dead link

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Hey, wanna pair our account on Brainly so we can share the perks? https://brainly.com/invite/8db681239ab5027e03b097bcded13755?ut
sashaice [31]

Answer:

Explanation:

NO Thx

8 0
3 years ago
Read 2 more answers
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
3 years ago
Assume that ip has been declared to be a pointer to int and that enrollment has been declared to be an array of 20 elements . As
Vitek1552 [10]

Answer:

ip = enrollment + section;

Explanation:

The variable ip has been declared to be a pointer to int.

int * ip;

The variable enrollment has been declared as an array of 20 elements .

int enrollment[20];

The variable section has been declared as an int.

int section;

In order to make ip point to the element in the array indexed by section, we can use the following statement :

ip = enrollment + section;

This will make ip point to enrollment[section].

5 0
3 years ago
Select the correct answer.
Softa [21]

Answer:

D. smart phone

explanation;

a. what the heck is a radio going to do?

b. an HD television? is his job watching movies?

d. he already has a form of communication he uses, he needs something that can to both things at the same time

c. a smart phone can do everything he needs to do, likely faster than a landline phone or laptop.

5 0
2 years ago
1. Which of the following is required to create a computer simulation?
Sonbull [250]
1. Data
2. Input
3. Experimentation
4. Calculates Physics
5. You owe me.
6. Do your work next time.
7. You will never be able to enjoy a nice pipe and gin and use an app like this like a trivia game if you don't force yourself to completely understand your work.
8. I sound like your dad.
9. I am right.
6 0
3 years ago
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