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zmey [24]
1 year ago
8

9- Write a program in MARIE to add three numbers.

Computers and Technology
1 answer:
Korvikt [17]1 year ago
8 0

A series of instructions written in a programming language for a computer to follow is referred to as a computer program.

<h3>What is program?</h3>

Software, which also contains documentation and other intangible components, comprises computer programs as one of its components.

The source code of a computer program is the version that can be read by humans. Since computers can only run their native machine instructions, source code needs to be run by another software.

Using the language's compiler, source code may be converted to machine instructions. (An assembler is used to translate programs written in machine language.) An executable is the name of the generated file.

Therefore, A series of instructions written in a programming language for a computer to follow is referred to as a computer program.

To learn more about program, refer to the link:

brainly.com/question/11023419

#SPJ1

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2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
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program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

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= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

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