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spin [16.1K]
2 years ago
7

Use the graph to find the following.

Mathematics
1 answer:
poizon [28]2 years ago
3 0

The values of x at wich F(x) has local minimums are x = -2 and x = 4, and the local minimums are:

  • F(-2) = -3
  • F(4) = -5

<h3>What is a local maximum/minimum?</h3>

A local maximum is a point on the graph of the function, such that in a close vicinity it is the maximum value there. So, on an interval (a, b) a local maximum would be F(c) such that:

c ∈ (a, b)

F(c) ≥ F(x) for ∀ x ∈ [a, b]

A local minimum is kinda the same, but it must meet the condition:

c ∈ (a, b)

F(c) ≤ F(x) for ∀ x ∈ [a, b]

A) We can see two local minimums, we need to identify at which values of x do they happen.

The first local minimum happens at x = -2

The second local minimum happens at x = 4.

B) The local minimums are given by F(-2) and F(4), in this case, the local minimums are:

  • F(-2) = -3
  • F(4) = -5

If you want to learn more about minimums/maximums, you can read:

brainly.com/question/2118500

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Question 3
hoa [83]

answer is (-7,2)

y = -x -5

y= x+9

Both equations have y on the left hand side

So we equate both equations

We replace -x-5 for  y in the second equation

-x -5 = x+9

Subtract x on both sides

-2x -5 = 9

Now add 5 on both sides

-2x = 14

Divide by -2 from both sides

x = -7

Now plug in -7 for x in the first equation

y = -x -5

y = -(-7)  -5= 7-5 = 2

So answer is (-7,2)

4 0
3 years ago
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Sveta_85 [38]
0, 1, 2

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3 years ago
Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.
topjm [15]

Given:

The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).

To find:

The fourth vertex of the parallelogram.

Solution:

Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).

We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Two diagonals of ABCD are AC and BD.

Midpoint of AC = Midpoint of BD

\left(\dfrac{-3+2}{2},\dfrac{8-5}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

\left(\dfrac{-1}{2},\dfrac{3}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

On comparing both sides, we get

\dfrac{4+a}{2}=\dfrac{-1}{2}

4+a=-1

a=-1-4

a=-5

And,

\dfrac{5+b}{2}=\dfrac{3}{2}

5+b=3

b=3-5

b=-2

Therefore, the coordinates of fourth vertex are (-5,-2).

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Answer:

Step-by-step explanation:

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