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Art [367]
2 years ago
11

Plz solve it is ergent ​

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
7 0

Answer:

first term = 2 ...(given)

second term = f (2) = f (2-1) * 5 = 1 * 5 = 5. .....[according to the formula f(n) = f (n -1) *5 ]

third term = f (3) = f ( 3 - 1 ) * 5 = 2 * 5 = 10

fourth term = f (4) = f (4 - 1) * 5 = 3 * 5.= 15

fivth term = f (5) = f ( 5 - 1) * 5 = 4* 5. =20

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Please help me. Factor. 5x^+23x+26
Alexus [3.1K]
<span>Algebra Calculator | Latest | Discuss | About | Help | Translation</span>

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Skip Ad <span> <span> <span> <span> </span> <span>
</span></span></span></span> <span><span> 5x2-23x=-26</span> </span>Two solutions were found :<span><span>  x = 2 </span><span>  x = 13/5 = 2.600
</span></span>

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     5*x^2-23*x-(-26)=0 

Step by step solution :Skip Ad
<span> Step  1  :</span><span>Equation at the end of step  1  :</span><span> (5x2 - 23x) - -26 = 0 </span><span> Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> 5x2-23x+26</span> 

The first term is, <span> <span>5x2</span> </span> its coefficient is <span> 5 </span>.
The middle term is, <span> -23x </span> its coefficient is <span> -23 </span>.
The last term, "the constant", is <span> +26 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span>  5 • 26 = 130</span> 

Step-2 : Find two factors of  130  whose sum equals the coefficient of the middle term, which is  <span> -23 </span>.

<span><span>       -130    +    -1    =    -131 <span>
</span> </span> <span>       -65    +    -2    =    -67 <span>
</span> </span> <span>       -26    +    -5    =    -31 <span>
</span> </span> <span>       -13    +    -10    =    -23    That's it</span></span>
4 0
3 years ago
This assignment is due tomorrow please help :(
Mariulka [41]
The answer would be 9 units squared hope this helped(:
6 0
2 years ago
Read 2 more answers
A dog chases a squirrel. The dog is originally 200 feet away from the squirrel. The dog's speed is 150 feet per minute. The squi
Dafna11 [192]

Answer:

15 seconds

Step-by-step explanation:

If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy:  the dog's rate is 150 and the squirrel's is 100.  The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know:  the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up.  Since we don't know what d is, we will just call it d!  Now it seems as though we have 2 unknowns which is a problem.  However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other.  Here's the dog's equation:

d = rt

d+200 = 150t

And the squirrel's:

d = 100t

If we solve both for t and set them equal to each other we have:

\frac{150}{d+200} =\frac{100}{d}

Now we can cross multiply to solve for d:

150d = 100d + 20,000 and

50d = 20,000

d = 400

But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took.  So sub that d value back into one of the equations we have solved for t and do the math:

t=\frac{100}{d}=\frac{100}{400} =\frac{1}{4}

That's 1/4 of a minute which is 15 seconds.

6 0
3 years ago
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For △RST and △UVW, ∠R≅∠U, ST≅VW, and ∠S≅∠v. Explain how you can prove △RST ≅△UVW by ASA
monitta

Answer:

See explanation below.

Step-by-step explanation:

Note that in △RST and △UVW

  • m∠T=180°-m∠R-m∠S;
  • m∠W=180°-m∠U-m∠V.

Since ∠R≅∠U and ∠S≅∠V, then ∠T≅∠W.

In ΔRST and ΔUVW:

  • ∠S≅∠V (given);
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  • ST≅VW (given).

ASA theorem that states that if two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

By ASA theorem ΔRST≅ΔUVW.

6 0
3 years ago
Which of the equations is graphed below?
Grace [21]

so you for sure cross off the 1st and 3rd problem off and if you choose the last one your answer would be in th left side of the y axis so it the 2nd answer

3 0
2 years ago
Read 2 more answers
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