If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
X=30 degrees for each of the congregant angles
Answer:
Step-by-step explanation:
Perimeter is 70 m
so w + w + 6w + 6w = 70
w = 70/14 = 5, l = 30m.
Area = l * w = 30 * 5 = 150 sq m
Answer:

Step-by-step explanation:
Either you wanted me to simplify all those variables or you just had a seizure on your keyboard.