Question

Write the equation of a line that passes through the points (6, 8) and ( -2, 4) in

Answer 1

Answer:

Equation of a line that passes through the points (6, 8) and ( -2, 4) in

slope intercept form is

$y =-\frac{1}{2} x + 11$

Step-by-step explanation:

General Equation of straight line is

$y-y_1 =\frac{y_2-y_1}{x_2-x_1}(x-x_1)$   ---------- (1)

Here

$(x_1, y_1) = (6, 8) \ \ and \ \ (x_2, y_2) = (-2, 4)$

Substituting values in (1)

$y-8 =\frac{4-8}{-2-6}(x-6)$

Simplifying it further

$y-8 =-\frac{1}{2}(x-6)$

$y =-\frac{1}{2} x + \frac{1}{2} 6 + 8$

$y =-\frac{1}{2} x + 3 + 8$

$y =-\frac{1}{2} x + 11$

Answer 2

Answer:

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Step-by-step explanation: